当使用XmlRootAttribute类时,我需要冲洗吗?
本文关键字:XmlRootAttribute 类时 | 更新日期: 2023-09-27 18:04:44
我知道当使用流时,我需要刷新它,这样它就会释放与流相关的任何资源,刷新流会获取任何尚未写入的缓冲数据,并立即将其写出来。
我有以下类:
[XmlRoot("EventList")]
public class EventList
{
private List<BaseEvent> events_ = new List<BaseEvent>();
/// Default constructor. Required for serialization
public EventList() {}
[XmlElement(ElementName = "Event")]
public List<BaseEvent> Events
{
get
{
return events_;
}
set
{
events_ = value;
}
}
}
现在,在我把它作为HTTPRequest的响应发送之前,我需要冲洗它吗?如果有,我怎么能呢?
我问,因为我有问题,描述如下:AJAX响应- XmlHttp。responseXML被截断
被js客户端激活的方法是:
[WebMethod]
public EventsRequestResult GetEvents(string agentId, int delayedReturnMS)
// EventsRequestResult - return value of the GetEvents method of the EventsService.
public class EventsRequestResult
{
private EventList events_ = null;
/// <summary>
/// List of the events
/// </summary>
[XmlElement(ElementName = "Events")]
public EventList Events
{
get
{
return events_;
}
set
{
events_ = value;
}
}
/// Default constructor.
public EventsRequestResult(){}
/// <summary>
/// Constructor used in case of the failure.
/// </summary>
/// <param name="errorCode">Numeric error code</param>
/// <param name="errorDescription">Human readable error description</param>
public EventsRequestResult(RequestErrorCode errorCode, string errorDescription) : base(errorCode, errorDescription){}
/// <summary>
/// Constructor used in case of successful events request.
/// </summary>
/// <param name="events">List of the events</param>
public EventsRequestResult(EventList events) : base()
{
events_ = events;
}
}
Marc的评论是对的,但我认为你要找的是类似
的东西 using(var stream = theResponse.OutputStream)
{
var ser = new XmlSerializer(typeof(EventList));
return ser.Deserialize(stream) as EventList;
}
return
from using block将关闭(并刷新)流