解析XML文档的建议
本文关键字:文档 XML 解析 | 更新日期: 2023-09-27 17:50:26
希望得到一些帮助:我非常感谢开发人员与我分享这个XML文件,因为它应该为我节省很多麻烦。但他告诉我,我要自己去读。基本上,我正在为一款纸牌游戏编写一个windows商店应用程序。我有一个XML,它是我的卡列表,我想把它读入列表。我没有得到任何错误,并且以前已经将XML读取到列表中。如有任何建议,不胜感激。
下面是一段XML代码:
<?xml version="1.0" encoding="UTF-8"?><carddatabase>
<cards>
<card>
<name>Tundra Kavu</name>
<set picURL="http://gatherer.wizards.com/Handlers/Image.ashx?multiverseid=26805&type=card" picURLHq="" picURLSt="">AP</set>
<color>R</color>
<manacost>2R</manacost>
<type>Creature - Kavu</type>
<pt>2/2</pt>
<tablerow>2</tablerow>
<text>{T}: Target land becomes a Plains or an Island until end of turn.</text>
</card>
</cards>
</carddatabase>
这是我的序列化器:
public async void readFile()
{
StorageFolder myFolder = ApplicationData.Current.LocalFolder;
StorageFile myFile = await myFolder.CreateFileAsync("cards.xml", CreationCollisionOption.OpenIfExists);
XmlSerializer Serializer = new XmlSerializer(typeof(List<card>), new XmlRootAttribute("carddatabase"));
string XmlString = await FileIO.ReadTextAsync(myFile);
XmlDocument xmlDoc = await XmlDocument.LoadFromFileAsync(myFile);
var settings = new XmlReaderSettings { ConformanceLevel = ConformanceLevel.Auto, IgnoreWhitespace = true, IgnoreComments = true };
var stringReader = new StringReader(XmlString);
XmlReader reader = XmlReader.Create(stringReader, settings);
List<card> temp = (List<card>)Serializer.Deserialize(reader);
foreach(card x in temp)
{
await tempTable.InsertAsync(x);
}
}
这是我的卡片类:
public class card
{
public string id { get; set; }
public string name { get; set; }
public string manacost { get; set; }
public string set { get; set; }
public string color { get; set; }
public string tablerow { get; set; }
public string text { get; set; }
public string type { get; set; }
}
您可以使用Linq:
解析xmlXDocument xdoc = XDocument.Load(myFile);
var cards = from c in xdoc.Descendants("card")
select new card() {
name = (string)c.Element("name"),
manacost = (string)c.Element("manacost"),
set = (string)c.Element("set"),
color = (string)c.Element("color"),
tableRow = (string)c.Element("tablerow"),
text = (string)c.Element("text"),
type = (string)c.Element("type")
};
foreach(var card in cards)
await tempTable.InsertAsync(card);
Linq还允许您将值从字符串转换为其他数据类型,因此您可以在类中拥有属性int TableRow { get; set; }
,它可以被解析为TableRow = (int)c.Element("tablerow")
(或int?
,如果不需要tablerow元素)。
public class Card
{
public string Id { get; set; }
public string Name { get; set; }
public string ManaCost { get; set; }
public string Set { get; set; }
public string Color { get; set; }
public int TableRow { get; set; }
public string Text { get; set; }
public string Type { get; set; }
}