c#通过xml循环获取特定子节点的innertext值
本文关键字:子节点 innertext 通过 xml 循环 获取 | 更新日期: 2023-09-27 18:04:50
我有一个像这样的XML文档:
<Runs>
<Run>
<LotInfo>
<Column name="Entity">HST123,</Column>
<Column name="Product">XXX123</Column>
<Column name="WSOp">1234</Column>
<Column name="Route">V234</Column>
<Column name="Recipe" />
<Column name="LotNumber">K898722</Column>
<Column name="RunStartTime">2014-05-20T17:43:11.8872105</Column>
</LotInfo>
<Operations>
<Operation type="INTRODUCTION">
<Column name="Size">1490</Column>
<Column name="TimeStamp">2014-05-20T17:43:11.8872105</Column>
<Column name="Operator">nismail9</Column>
<Column name="Description">
<![CDATA[ Unknown ]]>
</Column>
<Column name="Status">Success</Column>
</Operation>
<Operation type="RNUCHECK">
<Column name="Size">1490</Column>
<Column name="TimeStamp">2014-05-20T17:43:15.3091731</Column>
<Column name="Operator">nismail9</Column>
<Column name="Description">
<![CDATA[ ]]>
</Column>
<Column name="Status">True</Column>
</Operation>
<Operations>
<Operation type="INTRODUCTION">
<Column name="Size">1490</Column>
<Column name="TimeStamp">2014-05-20T17:58:47.0830259</Column>
<Column name="Operator">nismail9</Column>
<Column name="Description">
<![CDATA[ Unknown ]]>
</Column>
<Column name="Status">Success</Column>
</Operation>
</Operations>
</Run>
</Runs>
我想循环遍历整个XML以获得内部文本值。我需要获取节点<Operation type="INTRODUCTION">
的时间戳。每当我获得<Operation type="INTRODUCTION">
时,我将去获取该节点下的时间戳:<Column name="TimeStamp">2014-05-20T17:43:11.8872105</Column>
即2014-05-20T17:43:11.8872105
。
我有一个代码来获取值,但我不知道如何循环通过整个文本来获得所有的值。我只能得到一个。
我的代码:
XmlDocument readDoc = new XmlDocument();
readDoc.Load(fileName);
int count = readDoc.SelectNodes("/Runs/Run/Operations/Operation[@type='INTRODUCTION']").Count;
MessageBox.Show(count.ToString());
var node = readDoc.SelectSingleNode("/Runs/Run/Operations/Operation[@type='INTRODUCTION']/Column[@name='TimeStamp']");
MessageBox.Show(node.InnerText);
您可以使用 SelectNodes
获取所有操作节点的内部文本,然后对其进行迭代以获取内部文本。
var nodes = readDoc.SelectNodes("/Runs/Run/Operations/Operation/
Column[@name='TimeStamp']");
var innerTexts = nodes.OfType<XmlNode>().Select(n => n.InnerText);
确保添加 System.Linq
命名空间以使用可枚举的扩展方法。
使用XmlDocument。选择节点而不是XmlDocument。选择tsinglenode获取所有匹配的节点。您不需要节点的计数,而是它们的列表。获得节点后,使用常规的foreach
循环结构遍历它们:
var xmlFile = "c:''input.xml";
XmlDocument readDoc = new XmlDocument();
readDoc.Load(xmlFile);
var nodes = readDoc.SelectNodes("/Runs/Run/Operations/Operation[@type='INTRODUCTION']/Column[@name='TimeStamp']");
foreach (XmlElement node in nodes)
{
Console.WriteLine(node.InnerText);
}
输出为:
2014-05-20T17:43:11.8872105
2014-05-20T17:58:47.0830259
另一种可能是使用LINQ2XML来获得所需的节点:
try
{
var xmlFile = "c:''input.xml";
// load the xml file
var xml = XDocument.Load(xmlFile);
// find all operations nodes
var operations = xml.Root.Descendants("Operations").ToList();
// iterate over all nodes
foreach (var operation in operations)
{
// find the operation node with type INTRODUCTION
var op = operation.Elements().Where (o => o.Name == "Operation" && (o.Attribute("type").Value.ToUpper() == "INTRODUCTION")).FirstOrDefault();
if (op != null)
{
// find the timestamp node
var timestamp = op.Elements().Where (o => o.Name == "Column" && (o.Attribute("name").Value.ToUpper() == "TIMESTAMP")).FirstOrDefault();
if (timestamp != null)
{
// and get the value
Console.WriteLine(timestamp.Value);
}
}
}
}
catch (Exception exception)
{
Console.WriteLine(exception.Message);
}
输出与上面相同:
2014-05-20T17:43:11.8872105
2014-05-20T17:58:47.0830259
在XML中使用LINQ
(using System.Xml.Linq;
)
var query = XDocument.Load(xmlPath)
.Descendants("Operation")
.Where(w => (string)w.Attribute("type") == "INTRODUCTION")
.SelectMany(s => s.Elements("Column")
.Where(w => (string)w.Attribute("name") == "TimeStamp")
.Select(x => (string)x));