Null model with ajax post

我正在尝试使用ajax post将模型传递给控制器，但每次我这样做时，模型为空，我失去了我试图坚持的所有数据。

ajax调用:

$('#next').click(function (e) {
    e.preventDefault();
    var url = '@Url.Action("Manage")'
    var _model = JSON.stringify(@Html.Raw(Json.Encode(Model)));
    var _page = @(Model.pager.CurrentPage + 1);
    $.ajax({
        type: "POST",
        contentType: "application/json; charset=utf-8",
        url: url,
        data: JSON.stringify({ 'model': _model, 'page': _page }),
        success: function(result) {
            console.log(result);
        }
    });
});

当我查看序列化对象时，它看起来像一个格式正确的JSON对象，没有在开发控制台抛出错误。

触发这个jQuery调用的链接只是一个基本的动作链接:

@Html.ActionLink(">", "Manage", "Announcements", null, new { id = "next" })

我的模型有点复杂…

public class ManageViewModel : IEnumerable<EditViewModel>
{
    [Display(Name="Start Date")]
    [DataType(DataType.DateTime)]
    public DateTime? StartDate { get; set; }
    [Display(Name="End Date")]
    [DataType(DataType.DateTime)]
    public DateTime? EndDate { get; set; }
    public string SearchString { get; set; }
    public Pager pager { get; set; }
    public List<EditViewModel> Data { get; set; }
    public List<CategoryViewModel> Categories { get; set; }
    public ManageViewModel()
    {
        Data = new List<EditViewModel>();
        Categories = new List<CategoryViewModel>();
    }
    public IEnumerator<EditViewModel> GetEnumerator()
    {
        return Data.GetEnumerator();
    }
    IEnumerator IEnumerable.GetEnumerator()
    {
        return Data.GetEnumerator();
    }
}
public class Pager
{
    public int TotalItems { get; private set; }
    public int CurrentPage { get; private set; }
    public int PageSize { get; private set; }
    public int TotalPages { get; private set; }
    public int StartPage { get; private set; }
    public int EndPage { get; private set; }
    public Pager(int totalItems, int? page, int pageSize = 10)
    {
        int totalPages = (int)Math.Ceiling((decimal)totalItems / (decimal)pageSize);
        int currentPage = page ?? 1;
        int startPage = currentPage - 5;
        int endPage = currentPage + 4;
        if(startPage <= 0)
        {
            endPage -= (startPage - 1);
            startPage = 1;
        }
        if(endPage > totalPages)
        {
            endPage = totalPages;
            if(endPage > 10)
            {
                startPage = endPage - 9;
            }
        }
        TotalItems = totalItems;
        TotalPages = totalPages;
        CurrentPage = currentPage;
        PageSize = pageSize;
        EndPage = endPage;
        StartPage = startPage;
    }
}

我不能将链接转换为表单，因为这会破坏分页。或者我只是没有完全理解。

这是视图中发生分页的部分

if (Model.pager.EndPage > 1)
{
    <div style="color:#337AB7; padding-bottom: 0px;">Page @Model.pager.CurrentPage of @Model.pager.TotalPages</div>
    <ul class="pagination">
        @if (Model.pager.CurrentPage > 1)
        {
            <li>
                @Html.ActionLink("<<", "Manage", new { model = Model, start = Model.StartDate, end = Model.EndDate, query = Model.SearchString }, null)
            </li>
            <li>
                @Html.ActionLink("<", "Manage", new { model = Model, page = Model.pager.CurrentPage - 1, start = Model.StartDate, end = Model.EndDate, query = Model.SearchString }, null)
            </li>
        }
        @for (var _page = Model.pager.StartPage; _page < Model.pager.EndPage + 1; _page++)
        {
            <li class="@(_page == Model.pager.CurrentPage ? "active" : "")">
                @Html.ActionLink(_page.ToString(), "Manage", new { model = Model, page = _page, start = Model.StartDate, end = Model.EndDate, query = Model.SearchString }, null)
            </li>
        }
        @if (Model.pager.CurrentPage < Model.pager.TotalPages)
        {
            <li> 
                @Html.ActionLink(">", "Manage", "Announcements", null, new { id = "next" })
            </li>
            <li>
                @Html.ActionLink(">>", "Manage", new { model = Model, page = Model.pager.TotalPages, start = Model.StartDate, end = Model.EndDate, query = Model.SearchString }, null)
            </li>
        }
    </ul>
}

试图传递模型的操作链接显然不起作用，但我离开了它们，因为我专注于让一个工作，前面列出的那个，在配置所有其他的之前。

我看了下面的SO帖子，没有找到它们:
Post MVC模型与AJAX?
从列表框更改事件
$.ajax() post request到MVC控制器方法
使用Jquery/Ajax将模型传递给控制器
如何在ajax post请求传递模型?

有什么办法可以让我做到这一点吗?我需要模型数据来保存搜索/过滤，这是通过表单完成的。提前感谢您的观看和您的见解!