如何检查在asp.net中是否启用或禁用了cookie

本文关键字：启用是否 cookie net 何检查检查 asp | 更新日期: 2023-09-27 18:05:39

protected void Page_Load(object sender, EventArgs e)
{
    if (!IsPostBack)
    {
        if (Request.Browser.Cookies)
        {
            if (Request.QueryString["check"] == null)
            {
                HttpCookie cookie = new HttpCookie("testcookie");
                Response.Cookies.Add(cookie);
                Response.Redirect("Default.aspx?check=1");
            }
            else
            {
                HttpCookie cookie = Request.Cookies["testcookie"];
                if(cookie==null)
                {
                    Label1.Text = "enable cookies";
                }
            }
        }
        else
        {
            Label1.Text = "cookies not supported:";
        }
    }
}
protected void Button1_Click(object sender, EventArgs e)
{
    HttpCookie cookie = new HttpCookie("userinfo");
    cookie["name"] = TextBox1.Text;
    cookie["email"] = TextBox2.Text;
    //cookie.Expires = DateTime.Now.AddDays(30);
    Response.Cookies.Add(cookie);
    Response.Redirect("Default2.aspx");
}

请看下面的链接。

启用http://forums.asp.net/t/1044823.aspx?How + +检查+饼干+ +在+ +网络+浏览器+

唯一的检查方法是设置一个cookie，然后重定向它，并再次检查您是否能够访问它。所以试试上面链接中提到的方法。

protected void Page_Load(object sender, EventArgs e)
{
    if (this.IsCookieDisabled())
      errorMsgLabel.Text = Resources.Resource.BrowserDontSupportCookies;
}

private bool IsCookieDisabled()
{
 string currentUrl = Request.RawUrl;
 if (Request.QueryString["cookieCheck"] == null)
 {
     try
     {
            HttpCookie c = new HttpCookie("SupportCookies", "true");
            Response.Cookies.Add(c);
            if (currentUrl.IndexOf("?") > 0)
                currentUrl = currentUrl + "&cookieCheck=true";
            else
                currentUrl = currentUrl + "?cookieCheck=true";
            Response.Redirect(currentUrl);
       }
       catch(Exception ex)
       {
          return false;
       }
 }
 if (!Request.Browser.Cookies || Request.Cookies["SupportCookies"] == null)
      return true;
return false;
}