在视图模型上投影的Linq组外连接
本文关键字:Linq 连接 投影 视图 模型 | 更新日期: 2023-09-27 18:05:53
在过去的两天里,我一直在互联网上寻找一个解决方案来对BookId上的以下linq查询进行分组,但无济于事。查询工作,但我想重新组织它,以便它可以分组BookId或BookTitle。
Book(BookId, Title, Author, ISBN, Location, BookTypeId, StockLogValue)
Booktype(BookTypeId, BookTypeName)
Stock(StockId, bookId, quantity, date_added)
Transact (transactionId, TransactionTypeId, BookId, Quantity, TransactDate)
TransactionType( TransactionTypeId, TransactionTypeName)
控制器public ActionResult Report(int? year, int? month, int? BkId)
{
var query = ReportYrMn( year, month, BkId);
return View(query);
}
public IEnumerable ReportYrMn(int? year, int? month, int? BkId)
{
var query =
(from bk in db.Books
join tr in db.Transacts.Where(a => a.TransactDate.Month == month && a.TransactDate.Year == year && a.TransactType.TransactTypeName == "sale") on bk.BookId equals tr.BookId into trs
from x in trs.DefaultIfEmpty()
join tr2 in db.Transacts.Where(a => a.TransactDate.Month == month && a.TransactDate.Year == year && a.TransactType.TransactTypeName == "gift") on bk.BookId equals tr2.BookId into trs2
from x2 in trs2.DefaultIfEmpty()
select new ReportViewModel { BookTitle = bk.BookTitle ,BookId = bk.BookId, StockLogValue=bksty.StockLogValue, SaleTotal = trs.Sum(c => c.TransactQty), GiftTotal = trs2.Sum(c => c.TransactQty), SalesCount = trs.Count(), GiftCount = trs2.Count() });
return query.AsEnumerable();
}
感谢您的帮助
立即解决您的问题是删除from a in b.DefaultIfEmpty()
行。join - into
与GroupJoin
相同,它创建与左侧项目相关的集合,即属于一本书的集合Transacs
。这正是你想要的。
后续的from
相当于SelectMany
,它再次使这些集合变平,使您得到一个扁平的图书交易行列表。
这就是你想要的:
var query =
(from bk in db.Books
join tr in db.Transacts
.Where(a => a.TransactDate.Month == month && a.TransactDate.Year == year && a.TransactType.TransactTypeName == "sale")
on bk.BookId equals tr.BookId into trs
join tr2 in db.Transacts
.Where(a => a.TransactDate.Month == month && a.TransactDate.Year == year && a.TransactType.TransactTypeName == "gift")
on bk.BookId equals tr2.BookId into trs2
select new ReportViewModel
{
BookTitle = bk.BookTitle,
BookId = bk.BookId,
StockLogValue=bksty.StockLogValue,
SaleTotal = trs.Sum(c => c.TransactQty),
GiftTotal = trs2.Sum(c => c.TransactQty),
SalesCount = trs.Count(),
GiftCount = trs2.Count()
});
我问关于导航属性,因为几乎总是他们使查询更容易编写,因为你不需要笨拙的join
s。但在你的情况下,差别并不是那么大。如果Book
有一个导航属性Transacts
,查询可能看起来像:
var query =
(from bk in db.Books
let sales = bk.Transacts
.Where(a => a.TransactDate.Month == month && a.TransactDate.Year == year && a.TransactType.TransactTypeName == "sale")
let gifts = bk.Transacts
.Where(a => a.TransactDate.Month == month && a.TransactDate.Year == year && a.TransactType.TransactTypeName == "gift")
select new ReportViewModel
{
BookTitle = bk.BookTitle,
BookId = bk.BookId,
StockLogValue=bksty.StockLogValue,
SaleTotal = sales.Sum(c => c.TransactQty),
GiftTotal = gifts.Sum(c => c.TransactQty),
SalesCount = sales.Count(),
GiftCount = gifts.Count()
});