如何在对象中格式化仅为字符串的属性，同时转换为json

本文关键字：属性 json 转换 字符串 对象 格式化 | 更新日期: 2023-09-27 18:07:18

实例类型不清楚。我使用Foo为例。我有一个格式方法和一个类，如下所示

public string FormatMethod(string s){
    //for example pattern ++
    return "++" + s + "++"; 
}
public class Foo{
    public int FooId {get;set;}
    public string Name {get;set;}
    public string Desciption {get;set;}
}
var foo = new Foo{ FooId = 1, Name = "FooName", Description = "Bla bla bla" };
// or
var list = new List<Foo>();
list.Add(foo);
var json = JsonConvert.SerializeObject(list);
//or
var jsonlist = JsonConvert.SerializeObject(foo);

我想在对象或列表中的字符串属性发送到格式方法，同时转换为json，

我希望json结果如下，

json结果

 {"FooId": 1 , "Name": "++FooName++", "Description" : "++Bla bla bla++" }

或作为列表

[{"FooId": 1 , "Name": "++FooName++", "Description" : "++Bla bla bla++" }]

我该怎么做?

编辑:

例如，

我想在对象序列化时应用任何模式如果名称为'FooName'，则序列化后需要为'++FooName++'。

我认为它可以使用我的转换器，但如何?

例如:

public class MyConverter : JsonConverter
    {
        public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
        {
            // need to do something in here, I don't know what to do.
        }
        public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
        {
            throw new NotImplementedException();
        }
        public override bool CanConvert(Type objectType)
        {
            throw new NotImplementedException();
        }
    }

如何在对象中格式化仅为字符串的属性，同时转换为json

转换器:

class StringFormatConverter : JsonConverter
{
    public string Format { get; set; }
    public override void WriteJson (JsonWriter writer, object value, JsonSerializer serializer)
    {
        writer.WriteValue(string.Format(Format, value));
    }
    public override object ReadJson (JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
    {
        throw new NotSupportedException();
    }
    public override bool CanConvert (Type objectType)
    {
        return objectType == typeof(string);
    }
}

用法:

Console.WriteLine(JsonConvert.SerializeObject(new List<Foo> {
    new Foo { FooId = 1, Name = "FooName", Description = "Bla bla bla" }
}, new JsonSerializerSettings {
    Converters = { new StringFormatConverter { Format = "++{0}++" } }
}));
输出:

[{"FooId":1,"Name":"++FooName++","Description":"++Bla bla bla++"}]

如果您需要将字符串修改限制为特定属性，您可以使用JsonConverterAttribute和JsonPropertyAttribute.ItemConverterType(并从JsonSerializerSettings中删除"全局"转换器)。

正确的方法可能是

    <
  1. 反序列化/gh>
  2. 执行字符串操作
  3. re-serialize

一样
// build initial Json
var foo = new Foo { FooId = 1, Name = "FooName", Desciption = "Bla bla bla" };
JavaScriptSerializer json_serializer = new JavaScriptSerializer();
string fooJson = json_serializer.Serialize(foo);
// change value in Json
Foo newFoo = json_serializer.Deserialize<Foo>(fooJson);
newFoo.Name = String.Format("++{0}++", newFoo.Name);
fooJson = json_serializer.Serialize(newFoo);

或者你想在转换为json之前格式化字符串，比如

Foo foo = new Foo { FooId = 1, Name = "FooName", Desciption = "Bla bla bla" };
Foo formattedFoo = new Foo { 
                             FooId = foo.FooId, 
                             Name = String.Format("++{0}++", foo.Name), 
                             Desciption = String.Format("++{0}++", foo.Desciption) 
                           };
JavaScriptSerializer json_serializer = new JavaScriptSerializer();
string fooJson = json_serializer.Serialize(formattedFoo);
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