我需要在javascript中实现这个c#方法.需要帮助吗?

本文关键字：方法 帮助 实现 javascript | 更新日期: 2023-09-27 18:08:36

我在c#.net的代码中使用了这个方法。我会将从数据库获取的日期传递到该方法的参数中，然后以非正式格式写入日期。现在我需要在jquery代码和

中实现同样的东西

我需要在这里使用这个函数。在我的JavaScript文件中，我将日期作为字符串。现在的问题是，我不知道如何将字符串转换为日期!那么我应该如何使用该日期并将其传递给这个函数?然后进行转换，例如.....(int) s.t oltoseconds;

给我一些想法，我怎么才能实现我想要的。我是JQuery的新手。

 static string GetInformalDate(DateTime d)
        {
            // 1.
            // Get time span elapsed since the date.
            TimeSpan s = DateTime.Now.Subtract(d);
            // 2.
            // Get total number of days elapsed.
            int dayDiff = (int)s.TotalDays;
            // 3.
            // Get total number of seconds elapsed.
            int secDiff = (int)s.TotalSeconds;
            // 4.
            // Don't allow out of range values.
            if (dayDiff < 0)
            {
                return null;
            }
            // 5.
            // Handle same-day times.
            if (dayDiff == 0)
            {
                // A.
                // Less than one minute ago.
                if (secDiff < 60)
                {
                    return "Just Now";
                }
                // B.
                // Less than 2 minutes ago.
                if (secDiff < 120)
                {
                    return "1 minute ago";
                }
                // C.
                // Less than one hour ago.
                if (secDiff < 3600)
                {
                    return string.Format("{0} minutes ago",
                        Math.Floor((double)secDiff / 60));
                }
                // D.
                // Less than 2 hours ago.
                if (secDiff < 7200)
                {
                    return "1 hour ago";
                }
                // E.
                // Less than one day ago.
                if (secDiff < 86400)
                {
                    return string.Format("{0} hours ago",
                        Math.Floor((double)secDiff / 3600));
                }
            }
            // 6.
            // Handle previous days, months and years.
            if (dayDiff == 1)
            {
                return "Yesterday";
            }
            if (dayDiff < 7)
            {
                return string.Format("{0} days ago",
                dayDiff);
            }
            if (dayDiff < 31)
            {
                return string.Format("{0} week(s) ago",
                Math.Ceiling((double)dayDiff / 7));
            }
            if (dayDiff < 365)
            {
                return string.Format("{0} month(s) ago", Math.Ceiling((double)dayDiff / 31));
            }
            else
            {
                return string.Format("{0} year(s) ago", Math.Ceiling((double)dayDiff / 365));
            }
            return null;
        }
@ IAbstractDownvoteFactory:我在那个聊天室。如果你还在这儿等着，你能来吗?需要帮助吗? 请问还有谁能帮我吗?

我需要在javascript中实现这个c#方法.需要帮助吗?

示例 

function GetUnformalDate(d) {
    // 1.
    // Get time span elapsed since the date.
    var s = new Date().getTime() - d.getTime();
    // 2.
    // Get total number of days elapsed.
    var dayDiff = (s / 86400000) | 0;
    // 3.
    // Get total number of seconds elapsed.
    var secDiff = s / (1000);
    // 4.
    // Don't allow out of range values.
    if (dayDiff < 0) {
        return null;
    }
    // 5.
    // Handle same-day times.
    if (dayDiff == 0) {
        // A.
        // Less than one minute ago.
        if (secDiff < 60) {
            return "Just Now";
        }
        // B.
        // Less than 2 minutes ago.
        if (secDiff < 120) {
            return "1 minute ago";
        }
        // C.
        // Less than one hour ago.
        if (secDiff < 3600) {
            return Math.floor(secDiff / 60) + " minutes ago";
        }
        // D.
        // Less than 2 hours ago.
        if (secDiff < 7200) {
            return "1 hour ago";
        }
        // E.
        // Less than one day ago.
        if (secDiff < 86400) {
            return Math.floor(secDiff / 3600) + " hours ago";
        }
    }
    // 6.
    // Handle previous days, months and years.
    if (dayDiff == 1) {
        return "Yesterday";
    }
    if (dayDiff < 7) {
        return dayDiff + " days ago";
    }
    if (dayDiff < 31) {
        return Math.ceil(dayDiff / 7) + " week(s) ago";
    }
    if (dayDiff < 365) {
        return Math.ceil(dayDiff / 31) + " month(s) ago";
    }
    else {
        return Math.ceil(dayDiff / 365) + " year(s) ago";
    }
    return null;
}

作为日期字符串，我们必须解析它:

var digits = "29-07-2011 12:51:33".match(/'d+/g);
var date = new Date(digits[2], digits[1], digits[0], digits[3], digits[4], digits[5])
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