从Android调用到c#的服务不工作

我想做的是将我的图像从Android发送到我的web服务，这是c#。在Android端，我没有得到任何错误和警告，但在服务上没有什么可显示的，它实际上从来没有得到图像。

我对这种方式的服务还是特别陌生，所以任何帮助都会非常感激!!

我的Android AsyncTask看起来像这样:

@Override
        protected String doInBackground(File... file) {
            String imageDescriptionTemp = "Photo Temp Description.";
            String PostRequestUri = "https://demo.relocationmw.com/ws_docmgmt/Service1.svc";
            HttpClient client = new DefaultHttpClient();
            HttpPost post = new HttpPost(PostRequestUri);
            FileBody bin1 = new FileBody(file[0]);
            MultipartEntity entity = new MultipartEntity(HttpMultipartMode.BROWSER_COMPATIBLE);
            entity.addPart("Image", bin1);
            post.setEntity(entity);
            HttpResponse response;
            try {
                response = client.execute(post);
                resEntity = response.getEntity();
                final String response_string = EntityUtils.toString(resEntity);
                if(resEntity != null){
                Log.i("RESPONSE", response_string); 
                }
            } catch (ClientProtocolException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            } catch (IOException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
            return null;
        }

这只是调用服务器上的服务文件，发送图像和很快的描述和一切。

这是我的 c# 服务代码。

using System;
using System.Collections.Generic;
using System.Linq;
using System.Runtime.Serialization;
using System.ServiceModel;
using System.ServiceModel.Web;
using System.Text;
using System.IO;
using System.Drawing;
using System.Drawing.Imaging;
using System.Xml;

// NOTE: You can use the "Rename" command on the "Refactor" menu to change the class name "Service1" in code, svc and config file together.
public class Service1 : IService1
{
    #region vars
    XmlDocument doc = new XmlDocument();// Create the XML Declaration, and append it to XML document
    XmlElement root;
    #endregion
    public Stream GetImage(string path)
    {
        FileStream stream = File.OpenRead(@System.Web.Hosting.HostingEnvironment.MapPath("~/attachments/test/") + "SrvTest.jpg");
        WebOperationContext.Current.OutgoingResponse.ContentType = "image/jpeg";
        return stream as Stream;
    }
    public XmlDocument UpImage(string path, Stream filecontents)
    {
        XmlDeclaration dec = doc.CreateXmlDeclaration("1.0", null, null);
        doc.PreserveWhitespace = true;
        doc.AppendChild(dec);// Create the root element
        root = doc.CreateElement("UpImage");
        doc.AppendChild(root);

        XmlElement xml_item;
        xml_item = doc.CreateElement("Response");
        Image img = System.Drawing.Image.FromStream(filecontents);
        img.Save(System.Web.Hosting.HostingEnvironment.MapPath("~/attachments/test/") + "SrvTest.jpg", ImageFormat.Jpeg);
        XmlElement item;
        item = doc.CreateElement("Success");
        item.InnerText = "Success";
        xml_item.AppendChild(item);
        return doc;
    }
}

这应该接受我的文件，并返回一个带有SUCCESS的XML供我记录。再次，任何帮助是非常感谢!