将字符串中的第一个字符与另一个字符串中的任意字符分组
本文关键字:字符 字符串 任意 第一个 另一个 | 更新日期: 2023-09-27 18:09:08
在给定字符串列表的Linq2Sql中,我需要一个查询,该查询返回具有以字符串中的任何字符开头的系统的所有字符串。
这是我想到的:(需要帮助这个函数)
void Main()
{
var strings = new List<string>(){"ABCDE", "FGHIJ", "KLMNO"};
var values = GetUsedStrings(strings);
/*
* In my case expected to return strings "ABCDE" and "KLMNO"
* since there exists Systems that starts
* with any of the characters in those strings.
*/
values.Dump();
}
public IList<string> GetUsedStrings(IList<string> strings)
{
var q = from s in tblSystems
where s.systemName != null && s.systemName.Length > 0
group s by s.systemName[0] into g //Somehow need to group by the characters strings list?
select g.Key;
return q.ToList();
}
单个字符串检查将是:(按预期工作)
private bool StartsWithAny(string characters)
{
return
(from s in tblSystems
where
s.systemName != null && s.systemName.Length > 0 &&
characters.Contains(s.systemName[0])
select s).Any();
}
试试这样:
private bool StartsWithAny(string characters)
{
string aa = @"if exists(select * from tblSystems where
systemName is not null and LEN(systemName)>0";
for (int i = 0; i < characters.Length; i++)
{
aa += " and SUBSTRING([login],1,1) = '" + characters[i] + "'";
}
aa+=")";
return db.ExecuteQuery<bool>(aa).Single();
}
如果你想从List中得到一个新的字符串,但这不会给你真正的组,这会解决你的问题吗?