如何为文件夹指定多个文件扩展名

本文关键字：文件 扩展名 文件夹 | 更新日期: 2023-09-27 18:09:27

我正在使用c#代码创建一个文件夹的。rar文件。

string zipFileToWrite, folderPath;
zipFileToWrite = @"D:'jack.zip";
folderPath = @"D:'New folder";
System.Diagnostics.Process MyProcess = new System.Diagnostics.Process();
MyProcess.StartInfo.WorkingDirectory = @"D:'NetworkPathChecking'FileBackup'FileBackup'bin'Debug'App_Files'";
MyProcess.StartInfo.FileName = "winrar.exe";
MyProcess.StartInfo.Arguments = "a -r " + "'"" + zipFileToWrite + "'"" + " " + "'"" + folderPath + "'"";
MyProcess.Start();
MyProcess.WaitForExit();

现在我需要指定多个扩展名作为从文件夹生成.rar的文件的过滤器。我该怎么做呢?

如何为文件夹指定多个文件扩展名

使用带有*. fileextension的文件列表可以解决这个问题。

程序
public static string RarFilesT(string rarPackagePath, Dictionary<int, string> accFiles)
{
   string error = "";
   try
   {
       string[] files = new string[accFiles.Count];
       int i = 0;
       foreach (var fList_item in accFiles)
       {
           files[i] = "'"" + fList_item.Value;
           i++;
       }
       string fileList = string.Join("'" ", files);
       fileList += "'"";
       System.Diagnostics.ProcessStartInfo sdp = new System.Diagnostics.ProcessStartInfo();
       string cmdArgs = string.Format("A {0} {1} -ep1 -r",
                String.Format("'"{0}'"", rarPackagePath),
                fileList);
       sdp.ErrorDialog = true;
       sdp.UseShellExecute = true;
       sdp.Arguments = cmdArgs;
       sdp.FileName = rarPath;//Winrar.exe path
       sdp.CreateNoWindow = false;
       sdp.WindowStyle = System.Diagnostics.ProcessWindowStyle.Hidden;
       System.Diagnostics.Process process = System.Diagnostics.Process.Start(sdp);
       process.WaitForExit();
       error = "OK";
   }
   catch (Exception ex)
   {
       error = ex.Message;
   }
   return error;
}

调用过程
private void btnSave_Click(object sender, EventArgs e)
{
    Dictionary<int, string> accFiles = new Dictionary<int, string>();
    accFiles.Add(1, @"D:'New folder'New folder'*.txt");
    accFiles.Add(2, @"D:'New folder'*.html");
    RarFilesT(@"D:'test.rar",accFiles );
}

现在这个过程工作得很好。

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