c#二进制写入返回更大的文件

本文关键字：文件 返回 二进制 | 更新日期: 2023-09-27 18:10:07

我在二进制写入器问题上遇到了一点麻烦，我的程序设置为加载SHIFT-JIS字符，并以相同的编码编写，但它返回的文件大小更大:s虽然我删除了几个字符，但这里是写入前后文件的示例，这些是打开和保存代码:

private void Openbtn_Click(object sender, EventArgs e)
    {
        listView1.Items.Clear();
        textBox1.Text = "";
        menuItem12.Text = "file type is: ";
        OpenFileDialog ofd = new OpenFileDialog();
        ofd.Title = "Open File";
        ofd.Filter = "All Files (*.*)|*.*";
        if (ofd.ShowDialog() == System.Windows.Forms.DialogResult.OK)
        {
            menuItem13.Enabled = true;
            menuItem14.Enabled = true;
            menuItem15.Enabled = true;
            path = ofd.FileName;
            BinaryReader br = new BinaryReader(File.OpenRead(path), Encoding.GetEncoding("SHIFT-JIS"));
            foreach (char mychar in br.ReadChars(4)) menuItem12.Text += mychar;
            if (menuItem12.Text != "file type is: TXTD")
            {
                MessageBox.Show("This is not a TXTD file...", "Sorry", MessageBoxButtons.OK, MessageBoxIcon.Error);
                return;
            }
            else
            {
                    MessageBox.Show("File opened Succesfully!", "Info", MessageBoxButtons.OK, MessageBoxIcon.Information);
                    br.BaseStream.Position = 0x8;
                    int Pntrnum = br.ReadInt16();
                    menuItem11.Visible = true;
                    menuItem11.Text = Pntrnum.ToString();
                    List<int> offsets = new List<int>();
                    br.BaseStream.Position = 0x10;
                    for (int i = 0; i < Pntrnum; i++)
                    {
                        offsets.Add(br.ReadInt32());
                    }
                    Dictionary<int, string> values = new Dictionary<int, string>();
                    for (int i = 0; i < offsets.Count; i++)
                    {
                        int currentOffset = offsets[i];
                        int nextOffset = (i + 1) < offsets.Count ? offsets[i + 1] : (int)br.BaseStream.Length;
                        int stringLength = (nextOffset - currentOffset - 1);
                        br.BaseStream.Position = currentOffset;
                        var chars = br.ReadChars(stringLength);
                        values.Add(currentOffset, new String(chars));
                    }
                    foreach (int offset in offsets)
                    {
                        listView1.Items.Add(offset.ToString("X")).SubItems.Add(values[offset]);
                    }
                    br.Close();
                    br = null;
            }
        }
        ofd.Dispose();
        ofd = null;
    }
private void Savebtn_Click(object sender, EventArgs e)
    {
        BinaryWriter bw = new BinaryWriter(File.OpenWrite(path));
        int number_pointers = Convert.ToInt32(menuItem11.Text);
        Encoding enc = Encoding.GetEncoding("SHIFT-JIS");
        bw.BaseStream.Position = 0x10;
        int curr_pointer = 16 + number_pointers * 4;
        //pointers writing
        for (int i = 0; i < number_pointers; i++)
        {
            bw.Write(curr_pointer);
            curr_pointer += enc.GetByteCount(listView1.Items[i].SubItems[1].Text) + ''0';
        }
        for (int i = 0; i < number_pointers; i++)
        {
            bw.Write(enc.GetBytes(listView1.Items[i].SubItems[1].Text + ''0'));
        }
        bw.Flush();
        bw.Close();
        bw = null;
    }

我真的很感谢你的帮助。

c#二进制写入返回更大的文件

查看您提供的Samples.zip中的"After"文件，似乎表明您输出了两次相同的字符串，或其他内容…

我建议你从较小的文件开始测试，并使用调试器介入。

实际上，我自己试过了，我想我发现了发生了什么:你使用"nextOffset - currentOffset"作为stringLength，但它实际上是一个字节长度…字符数组将在这个数字的一半之后结束(其中有一个''0')，并且在输出时还将得到您尚未读取的另一半。

[编辑]下面是我的评论代码，为了更好的格式:

int index;
for (index = 0; index < stringLength; ++index) if (chars[index] == ''0') break;
if (index < stringLength) {
    char[] relevantPart = new char[index];
    Array.Copy(chars, relevantPart, index);
    chars = relevantPart;
}
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