Json.NET反序列化自定义对象返回null

本文关键字：返回 null 对象 自定义 NET 反序列化 Json | 更新日期: 2023-09-27 18:10:11

我在使用Json.NET将JSON字符串转换为c#对象时遇到了麻烦。

我使用AJAX调用。ashx

$.ajax({
    url: "/Handler/Handler.ashx?WorkType=SaveData",
    type: "POST",
    data: JSON.stringify({ 'DataInfo': Info }),
    //data: "{'DataInfo':" + JSON.stringify(Info) + "}",
    dataType: "json",
    success: function (data, textStatus, jqXHR) {
        if (data.Result) {
        }
    },
    error: function (jqXHR, textStatus, errorThrown) {
        alert("Error '" + jqXhr.status + "' (textStatus: '" + textStatus + "', errorThrown: '" + errorThrown + "')");
    }
});

Json字符串是

{
   "DataInfo": [
      {
         "EditType": "Create",
         "CustCode": "SSG",
         "KeyNoStr": "rgrg",
         "Requester": "rgrg",
         "VerificationCode": "VAVBZ",
         "Databody": "TESt123",
         "HasMap": false,
         "IsColse": false,
         "HasOrder": false,
         "IsUrgent": true
      }
   ]
}

和我的。ashx服务器端代码像…

public class DataInfo
{
    public string EditType { get; set; } 
    public string CustCode { get; set; }
    public string KeyNoStr { get; set; }
    public string Requester { get; set; }
    public string VerificationCode { get; set; }
    public string Databody { get; set; }
    public string HasMap { get; set; }
    public string IsColse { get; set; }
    public string HasOrder { get; set; }            
    public string IsUrgent { get; set; }
}

.ashx中的main函数

public void ProcessRequest(HttpContext context)
{
    Request = context.Request;
    Response = context.Response;
    string lv_strResult = string.Empty;
    DataInfo lv_oInfo = JsonConvert.DeserializeObject<DataInfo >((new StreamReader(Request.InputStream)).ReadToEnd());
}

我做错了什么?

Json.NET反序列化自定义对象返回null

这是因为JSON对象是DataInfo的数组，所以需要使用这些类进行反序列化

public class DataInfo
{
    public string EditType { get; set; }
    public string CustCode { get; set; }
    public string KeyNoStr { get; set; }
    public string Requester { get; set; }
    public string VerificationCode { get; set; }
    public string Databody { get; set; }
    public bool HasMap { get; set; }
    public bool IsColse { get; set; }
    public bool HasOrder { get; set; }
    public bool IsUrgent { get; set; }
}
public class RootObject
{
    public List<DataInfo> DataInfo { get; set; }
}
//your method
public void ProcessRequest(HttpContext context)
{
    Request = context.Request;
    Response = context.Response;
    string lv_strResult = string.Empty;
    DataInfo lv_oInfo = JsonConvert.DeserializeObject<RootObject>((new StreamReader(Request.InputStream)).ReadToEnd());
 }

您的JSON表示具有一个名为DataInfo的类型为List<DataInfo>的属性的结构

所以你需要用

代替DataInfo lv_oInfo = JsonConvert.DeserializeObject<DataInfo >((new StreamReader(Request.InputStream)).ReadToEnd());
var jobject = (JObject)JsonConvert.DeserializeObject((new StreamReader(Request.InputStream)).ReadToEnd());
var di_json = jobject["DataInfo"].ToString();   // Dirty but this is the main idea
var data_infos = JsonConvert.DeserializeObject<List<DataInfo>>(di_json);

由于双重反序列化，这不是世界上最好的代码，但它显示了思想

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