更有效的方式来获得当前的星期和运行代码

本文关键字：运行 代码 方式 有效 | 更新日期: 2023-09-27 18:10:13

我在这里有一段效率极低的代码，它做了一个相当简单的工作-检测它是星期几，并使用字符串设置一堆文本框。代码工作得很好，但我认为有更好的方法来做到这一点?

if (DateTime.Now.DayOfWeek == DayOfWeek.Monday)
                {
                    time7.Text = "TUESDAY";
                    time8.Text = "WEDNESDAY";
                    time9.Text = "THURSDAY";
                    time10.Text = "FRIDAY";
                    time11.Text = "SATURDAY";
                    time12.Text = "SUNDAY";
                    time13.Text = "MONDAY";
                }
                if (DateTime.Now.DayOfWeek == DayOfWeek.Tuesday)
                {
                    time7.Text = "WEDNESDAY";
                    time8.Text = "THURSDAY";
                    time9.Text = "FRIDAY";
                    time10.Text = "SATURDAY";
                    time11.Text = "SUNDAY";
                    time12.Text = "MONDAY";
                    time13.Text = "TUESDAY";
                }
                if (DateTime.Now.DayOfWeek == DayOfWeek.Wednesday)
                {
                    time7.Text = "THURSDAY";
                    time8.Text = "FRIDAY";
                    time9.Text = "SATURDAY";
                    time10.Text = "SUNDAY";
                    time11.Text = "MONDAY";
                    time12.Text = "TUESDAY";
                    time13.Text = "WEDNESDAY";
                }
                if (DateTime.Now.DayOfWeek == DayOfWeek.Thursday)
                {
                    time7.Text = "FRIDAY";
                    time8.Text = "SATURDAY";
                    time9.Text = "SUNDAY";
                    time10.Text = "MONDAY";
                    time11.Text = "TUESDAY";
                    time12.Text = "WEDNESDAY";
                    time13.Text = "THURSDAY";
                }
                if (DateTime.Now.DayOfWeek == DayOfWeek.Friday)
                {
                    time7.Text = "SATURDAY";
                    time8.Text = "SUNDAY";
                    time9.Text = "MONDAY";
                    time10.Text = "TUESDAY";
                    time11.Text = "WEDNESDAY";
                    time12.Text = "THURSDAY";
                    time13.Text = "FRIDAY";
                }
                if (DateTime.Now.DayOfWeek == DayOfWeek.Saturday)
                {
                    time7.Text = "SUNDAY";
                    time8.Text = "MONDAY";
                    time9.Text = "TUESDAY";
                    time10.Text = "WEDNESDAY";
                    time11.Text = "THURSDAY";
                    time12.Text = "FRIDAY";
                    time13.Text = "SATURDAY";
                }
                if (DateTime.Now.DayOfWeek == DayOfWeek.Sunday)
                {
                    time7.Text = "MONDAY";
                    time8.Text = "TUESDAY";
                    time9.Text = "WEDNESDAY";
                    time10.Text = "THURSDAY";
                    time11.Text = "FRIDAY";
                    time12.Text = "SATURDAY";
                    time13.Text = "SUNDAY";
                }

更有效的方式来获得当前的星期和运行代码

var textBoxes = new List<TextBox>{time7, time8};//add others
var current = DateTime.Now;
foreach(var tb in textBoxes)
{
  current = current.AddDays(1);
  tb.Text = current.DayOfWeek.ToString().ToUpper();
}

类似这样的东西，你也可以使用其他的变体，比如for(var i = 0...)循环，但是你明白了。

另外，您可以使用MVVM模式绑定到textboxes，这更容易。

1)创建文本框数组

2)设置动态数(0 ~ 6)为天

3)然后用循环函数

填充文本框
for(i=0;i<=6:i++)
{textbox[i].text=dynamic_function_in_form_load(i);}

这个怎么样:

void YourFunction()
{
    // a list of your day-names: since it seems that you are maintaining some old code, I presume that implementation of localization is out of question, so you can use a list..
    var dateNames = new List<string>() { "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday", "Sunday" };
    // a list of your textboxes that hold names of days
    var tbs = new List<TextBox>() { textBox1, textBox2, textBox3, textBox4, textBox5, textBox6, textBox7 };
    // current day
    var x = (int)DateTime.Now.DayOfWeek;
    shift(dateNames, tbs, x);
}
void shift(List<string> dates, List<TextBox> tbs, int x)
{
    for (int i = 0; i < x; i++)
    {
        dates.Insert(7, dates[0]);
        dates.Remove(dates[0]);
    }
    for (int i = 0; i < dates.Count; i++)
    {
        tbs[i].Text = dates[i];
    }
}

这并不"好"，但仍然比你现在的维护更容易。

这个适合我:

var labels =
    typeof(DayOfWeek).GetEnumNames()
        .Concat(typeof(DayOfWeek).GetEnumNames())
        .Skip((int)DateTime.Now.DayOfWeek + 1)
        .Take(7)
        .Select(x => x.ToUpperInvariant())
        .ToArray();
 time7.Text = labels[0];
 time8.Text = labels[1];
 time9.Text = labels[2];
 time10.Text = labels[3];
 time11.Text = labels[4];
 time12.Text = labels[5];
 time13.Text = labels[6];
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