计算机科学- c# SimpleCalculator
本文关键字：SimpleCalculator 计算机科学 | 更新日期: 2023-09-27 17:50:59
我正试图为SIMPLE Calculator编写代码，我得到一些错误:
下面是错误:
错误1名称"Valid"在当前上下文中不存在
错误2名称"减"/"加"/"乘"、"除"在当前上下文中不存在
请看看什么是错误的代码和建议我做错了。
int input = 0;
double num1 = 0;
double num2 = 0;
string inputN1 = "";
string inputN2 = "";
bool validnum1 = true;
bool validnum2 = true;
do{
Console.WriteLine("Simple Calculator'n't 1) Add'n't 2) Subtract'n't 3)
Multiply'n't 4) Divide'n't 5) Quit'n't ", input);
Console.Write("Enter your Selection: ");
input = Convert.ToInt32(Console.ReadLine());
if (input ==5)
{
Console.WriteLine();
}
else if (input >5)
{
Console.WriteLine("Invalid Selection.'t Please Try Again");
}
else
{
Console.Write("Enter Number 1: ");
inputN1 = Console.ReadLine();
validnum1 = Valid(inputN1);
Console.Write("Enter Number 2: ");
validnum2 = Valid(inputN2);
if (validnum1 == true && validnum2 == true)
{
num1 = Convert.ToDouble(inputN1);
num2 = Convert.ToDouble(inputN2);
}
else
{
Console.WriteLine("Invalid Number Entered");
Console.ReadKey();
break;
}
switch (input)
{
case 1:
Console.WriteLine("'tResults: {0}", Add(num1, num2));
break;
case 2:
Console.WriteLine("'tResults: {0}", Subtract(num1, num2));
break;
case 3:
Console.WriteLine("'tResults: {0}", Multiply(num1, num2));
break;
case 4:
if (num2 == 0)
{
Console.WriteLine("Cant Divide by Zero/'t Please try Again");
}
else
{
Console.WriteLine("'tResults: {0}", Divide(num1, num2));
}
break;
}
Console.WriteLine("Press any key...");
Console.ReadKey();
Console.Clear();
}
}while (input != 5 && input <5);
Console.WriteLine("Press any key....");
Console.ReadKey();
}
}
}
首先，c#中没有有效、减法、加法和乘法这样的东西。检查给定的字符串是否有效double使用double.TryParse()。对于算术运算，分别使用+，-，*，/进行加，减，乘和除。相反，尝试使用这个代码，它将工作。如果您正在使用方法，那么通过类说明符访问它们，如Your_Class.Add()，因为要从静态类访问非静态方法，您需要包含非静态方法的类实例。
int input = 0;
double num1 = 0;
double num2 = 0;
string inputN1 = "";
string inputN2 = "";
bool validnum1 = true;
bool validnum2 = true;
do{
Console.WriteLine("Simple Calculator'n't 1) Add'n't 2) Subtract'n't 3) Multiply'n't 4) Divide'n't 5) Quit'n't ", input);
Console.Write("Enter your Selection: ");
input = Convert.ToInt32(Console.ReadLine());
if (input ==5)
{
Console.WriteLine();
}
else if (input >5)
{
Console.WriteLine("Invalid Selection.'t Please Try Again");
}
else
{
Console.Write("Enter Number 1: ");
inputN1 = Console.ReadLine();
validnum1 = double.TryParse(inputN1,out num1);
Console.Write("Enter Number 2: ");
inputN2 = Console.ReadLine();
validnum2 = double.TryParse(inputN2,out num2);
if (validnum1 != true || validnum2 != true)
{
Console.WriteLine("Invalid Number Entered");
Console.ReadKey();
break;
// num1 = Convert.ToDouble(inputN1);
// num2 = Convert.ToDouble(inputN2);
}
//else else will not be required as double.tryparse is succeeded then value will automatically assigned to respective numbers.
//{
//}
switch (input)
{
case 1:
Console.WriteLine("'tResults: {0}", num1+num2);
break;
case 2:
Console.WriteLine("'tResults: {0}", num1-num2);
break;
case 3:
Console.WriteLine("'tResults: {0}", num1*num2);
break;
case 4:
if (num2 == 0)
{
Console.WriteLine("Cant Divide by Zero/'t Please try Again");
}
else
{
Console.WriteLine("'tResults: {0}", num1/num2);
}
break;
}
Console.WriteLine("Press any key...");
Console.ReadKey();
Console.Clear();
}
}while (input != 5 && input <5);
Console.WriteLine("Press any key....");
Console.ReadKey();
}
}
}