选择许多字典问题

本文关键字：问题 字典 许多 选择 | 更新日期: 2023-09-27 17:51:15

我正在努力使用Linq语句从项目列表中获取项目列表并转换为字典。

我有一个"Windows"列表，其中有一个"控件"列表，但一个控件类型也有一个控件列表，我似乎无法弄清楚(就在我以为我理解Linq的时候:))

当前工作的嵌套foreach循环

    public static Dictionary<int, Dictionary<int, bool>> _windowControlVisibilityMap = new Dictionary<int, Dictionary<int, bool>>();
    public static void RegisterControlVisibility(IEnumerable<GUIWindow> windows)
    {
        _windowControlVisibilityMap.Clear();
        foreach (var window in windows)
        {
            var controlMap = new Dictionary<int, bool>();
            foreach (var control in window.Controls)
            {
                if (control is GUIGroup)
                {
                    foreach (var grpControl in (control as GUIGroup).Controls)
                    {
                        controlMap.Add(grpControl.ControlId, grpControl.IsWindowOpenVisible);
                    }
                }
                controlMap.Add(control.ControlId, control.IsWindowOpenVisible);
            }
            _windowControlVisibilityMap.Add(window.WindowId, controlMap);
        }
    }

我在Linq查询中做同样的荒谬尝试。(不工作)

    public static Dictionary<int, Dictionary<int, bool>> _windowControlVisibilityMap = new Dictionary<int, Dictionary<int, bool>>();
    public static void RegisterControlVisibility2(IEnumerable<GUIWindow> windows)
    {
        _windowControlVisibilityMap.Clear();
        foreach (var window in windows)
        {
            var dictionary = window.Controls.Select(k => new KeyValuePair<int, bool>(k.ControlId, k.IsWindowOpenVisible))
                .Concat(window.Controls.OfType<GUIGroup>().SelectMany(grp => grp.Controls)
                .Select(k => new KeyValuePair<int, bool>(k.ControlId, k.IsWindowOpenVisible)));
           // _windowControlVisibilityMap.Add(window.WindowId, dictionary);
        }
    }

如果有人能给我指出正确的方向，让这个Linq语句工作，那就太棒了:)

这里有一些模拟对象来帮助你帮助我，LOL

public class GUIWindow
{
    public int WindowId { get; set; }
    public List<GUIControl> Controls { get; set; }
}
public class GUIControl
{
    public int ControlId { get; set; }
    public bool IsWindowOpenVisible { get; set; }
}
public class GUIGroup : GUIControl
{
    public List<GUIControl> Controls { get; set; }
}

谢谢

选择许多字典问题

下面应该可以工作:

window.Controls.Select(x => new { x.ControlId, x.IsWindowOpenVisible })
      .Concat(window.Controls
                    .OfType<GUIGroup>()
                    .SelectMany(x => x.Controls)
                    .Select(x => new { x.ControlId, x.IsWindowOpenVisible }))
      .ToDictionary(x => x.ControlId, x => x.IsWindowOpenVisible);

但是哈姆雷特有一个有效的观点:GUIGroup中的每个控件都可以是另一个GUIGroup。你需要递归来解决这个问题:

Func<IEnumerable<GUIControl>, IEnumerable<Tuple<int, bool>> getValues = null;
getValues = x => x.Select(x => Tuple.Create(x.ControlId, x.IsWindowOpenVisible))
                  .Concat(getValues(window.Controls
                                          .OfType<GUIGroup>()
                                          .SelectMany(x => x.Controls)));
getValues(window.Controls).ToDictionary(x => x.Item1, x => x.Item2);
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