我怎么能嘲笑这段代码呢?
本文关键字:代码 段代码 怎么能 | 更新日期: 2023-09-27 17:51:18
我想开始模拟一些代码,但我不确定如何做到这一点。我读过一些教程,但我不能把它应用到我的代码中(这背后可能有原因)。我用的是NUnit和Moq。(我已经删除了所有其他的方法,所以我可以给你看一个)。
Api接口:
public interface IApiRequest
{
Task<T> ExecuteAsync<T>(RestRequest request);
}
我要Mock的方法:
public async Task<UpcomingMovies> GetUpcomingMovies(int page)
{
var request = new RestRequest
{
Resource = "movie/upcoming",
};
request.AddParameter("page", page.ToString());
request.AddParameter("language", "en");
var api = new ApiRequest();
return await api.ExecuteAsync<UpcomingMovies>(request);
}
我不知道如何嘲笑这个。
更新:这现在是一个有效的测试吗?
Mock<IApiRequest> mock = new Mock<IApiRequest>();
mock.Setup(x => x.ExecuteAsync<UpcomingMovies>(It.IsAny<RestRequest>()))
.Returns(Task.FromResult<UpcomingMovies>(new UpcomingMovies()));
如果您想模拟ExecutAsync
方法,您可以这样做:
Mock<IApiRequest> mock = new Mock<IApiRequest>();
mock.Setup(x => x.ExecuteAsync<UpcomingMovies>(It.IsAny<RestRequest>()))
.Returns(Task.FromResult<UpcomingMovies>(/** whatever movies **/));
如果您想模拟一个特定的请求,将It.IsAny<RestRequest>()
替换为对您的请求的引用。
要有效地测试你的类,你需要这样做:
public class MyClass
{
public MyClass(IApiRequest api)
{
this.api = api;
}
public async Task<UpcomingMovies> GetUpcomingMovies(int page)
{
var request = new RestRequest
{
Resource = "movie/upcoming",
};
request.AddParameter("page", page.ToString());
request.AddParameter("language", "en");
return await api.ExecuteAsync<UpcomingMovies>(request);
}
}
[Test]
public async Task MyTest()
{
var expectedMovies = new UpcomingMovies(); // or whatever movies you need
Mock<IApiRequest> mock = new Mock<IApiRequest>();
mock.Setup(x => x.ExecuteAsync<UpcomingMovies>(It.IsAny<RestRequest>()))
.Returns(Task.FromResult<UpcomingMovies>(expectedMovies));
var myClass = new MyClass(mock.Object);
var result = await myClass.GetUpcomingMovies(1);
Assert.IsTrue(expectedMovies == result);
}