如何将信息从一个窗口发送到另一个窗口?WPF

本文关键字：窗口 另一个 WPF 一个 信息 | 更新日期: 2023-09-27 18:14:39

如何将信息从一个wpf窗口发送到另一个窗口。我想要的是string filepath保存它第一次被调用时得到的信息。

这就是问题所在，当我从window1. xml .cs单击button1时，它从DocumentManager.cs调用openfile()。当我从window2. xml .cs访问filepath时，它给出了一个空字符串。我想保存从window1。xml。cs调用时得到的文件路径字符串。

我有:

window1.xmal.cs 

DocumentManager mgr = new DocumentManager();
private void Button1_Click(object sender, RoutedEventArgs e) {
        ImageSource imgsource = new BitmapImage(new Uri(mgr.openfile().ToString())); 
        themeImage.Source = imgsource;
}

DocumentManager.cs 

public string filePath;
public object openfile() {
    OpenFileDialog open = new OpenFileDialog();
    bool? result = open.ShowDialog();
    if (result == true) {
        filePath = open.FileName;  
    }
    return filePath;
}

如何将信息从一个窗口发送到另一个窗口?WPF

我认为你的问题是你实例化DocumentManager类的方式。
我举了一个有效的例子。下面是代码:

主窗口 

public partial class MainWindow : Window
{   DocumentManager mgr;       
    Window2 w2;
    public MainWindow() { InitializeComponent(); }
    private void MainWindow_Loaded(object sender, RoutedEventArgs e)
    {  mgr = new DocumentManager(); w2 = new Window2(); w2.Show(); }
    private void Button_Click(object sender, RoutedEventArgs e)
    { ImageSource imgsource; string imglocation;
        try {
            imglocation = mgr.openfile().ToString();
            imgsource = new BitmapImage(new Uri(imglocation));
            result.Text = imglocation;
            w2.imgsource = imgsource;
        }
        catch (Exception ex)
        { System.Windows.MessageBox.Show(ex.Message); }
    }
}

DocumentManager 

class DocumentManager
{
    public string filePath;
    public string openfile()
    {
        Microsoft.Win32.OpenFileDialog open = new Microsoft.Win32.OpenFileDialog();
        bool? result = open.ShowDialog();
        if (result == true) { filePath = open.FileName; }
        else { filePath = "Nothing Opened"; }
        return filePath;
    }
}

MainWindow XAML

<Window x:Class="CrossClassDialog.MainWindow"
    xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
    xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
    Title="MainWindow" Height="120" Width="350" Loaded="MainWindow_Loaded">
    <Grid>
        <Button Content="Button" HorizontalAlignment="Left" VerticalAlignment="Top" Click="Button_Click"/>
       <TextBlock x:Name="result" HorizontalAlignment="Left" Text="TextBlock" VerticalAlignment="Top" Margin="0,30,0,0"/>
    </Grid>
</Window>

Window2 XAML 

<Window x:Class="CrossClassDialog.Window2"
    xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
    xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
    Title="Window2" Height="300" Width="300">
<Grid>
    <Viewbox HorizontalAlignment="Left" VerticalAlignment="Top">
        <Image x:Name="OpenedImage" Source="{Binding ImageSource}" />
    </Viewbox>
</Grid>
</Window>

在windows2中添加此属性

    private ImageSource _imgsource;
    public ImageSource imgsource
    {
        get { return _imgsource; }
        set 
        { 
            _imgsource = value;
            OpenedImage.Source = value;
        }
    }

顺便说一下，我改变了一些东西，比如你的openfile()方法返回的类型。

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