我如何正确地定位上下文菜单,当我右键单击一个DataGridView's列标题
本文关键字:DataGridView 一个 标题 定位 正确地 上下文 菜单 右键 单击 | 更新日期: 2023-09-27 18:15:10
我想扩展DataGridView以添加第二个ContextMenu,以选择哪些列在网格中可见。新的ContextMenu将在右击列标题时显示。
我很难得到正确的水平位置来显示上下文菜单。我怎样才能纠正这个问题呢?
public partial class Form1 : Form
{
DataGridView dataGrid;
ContextMenuStrip contextMenuStrip;
public Form1()
{
InitializeComponent();
dataGrid = new DataGridView();
Controls.Add(dataGrid);
dataGrid.Dock = System.Windows.Forms.DockStyle.Fill;
dataGrid.ColumnHeaderMouseClick += new System.Windows.Forms.DataGridViewCellMouseEventHandler(ColumnHeaderMouseClick);
dataGrid.DataSource = new Dictionary<string, string>().ToList();
contextMenuStrip = new ContextMenuStrip();
contextMenuStrip.Items.Add("foo");
contextMenuStrip.Items.Add("bar");
}
private void ColumnHeaderMouseClick(object sender, DataGridViewCellMouseEventArgs e)
{
if (e.Button == System.Windows.Forms.MouseButtons.Right)
{
contextMenuStrip.Show(PointToScreen(e.Location));
}
}
}
这是一个非常简单的方法,使上下文菜单出现在你右键单击它的地方。
处理事件ColumnHeaderMouseClick
private void grid_ColumnHeaderMouseClick(object sender, DataGridViewCellMouseEventArgs e)
{
if (e.Button == System.Windows.Forms.MouseButtons.Right)
contextMenuHeader.Show(Cursor.Position);
}
contextMenuHeader
是一个ContextMenuStrip
,可以在Designer视图中定义,也可以在运行时定义。
要获取鼠标光标的坐标,可以这样做。
ContextMenu.Show(this, myDataGridView.PointToClient(Cursor.Position));
您是否尝试过使用接受控件和位置的Show重载?
例如:contextMenuStrip.Show(dataGrid, e.Location);
编辑:完整的例子
public partial class Form1 : Form
{
DataGridView dataGrid;
ContextMenuStrip contextMenuStrip;
public Form1()
{
InitializeComponent();
dataGrid = new DataGridView();
Controls.Add(dataGrid);
dataGrid.Dock = System.Windows.Forms.DockStyle.Fill;
dataGrid.MouseDown += MouseDown;
dataGrid.DataSource = new Dictionary<string, string>().ToList();
contextMenuStrip = new ContextMenuStrip();
contextMenuStrip.Items.Add("foo");
contextMenuStrip.Items.Add("bar");
}
private void MouseDown(object sender, MouseEventArgs e)
{
if (e.Button == System.Windows.Forms.MouseButtons.Right)
{
if (dataGrid.HitTest(e.X, e.Y).Type == DataGridViewHitTestType.ColumnHeader)
{
contextMenuStrip.Show(dataGrid, e.Location);
}
}
}
}
e.Location
不显示弹出式菜单在正确的坐标,而只是使用MousePosition
属性如下:
ContextMenuStrip.Show(MousePosition)
,或者影响
ContextMenuStrip.Show(Control.MousePosition)
返回的位置是相对于单元格的。所以我们要加上偏移量
private void grdView_CellMouseClick(object sender, DataGridViewCellMouseEventArgs e)
{
if (e.Button == MouseButtons.Right)
{
var pos = ((DataGridView)sender).GetCellDisplayRectangle(e.ColumnIndex,
e.RowIndex, false).Location;
pos.X += e.X;
pos.Y += e.Y;
contextMenuStrip.Show((DataGridView)sender,pos);
}
}
终于成功了。
ContextMenu.Show(myDataGridView, myDataGridView.PointToClient(Cursor.Position));
两次调用Show
将获得光标的确切位置。这个答案是为那些无法得到以上所有答案的结果的人准备的。
private void MouseDown(object sender, MouseEventArgs e)
{
if (e.Button == System.Windows.Forms.MouseButtons.Right)
{
contextMenuStrip.Show(dataGrid, e.Location));
contextMenuStrip.Show(Cursor.Position);
}
}
我出错的地方是DataGridViewCellMouseEventArgs返回鼠标在列标题中单击的位置/x,y。相反,我需要在网格的MouseDown事件中使用HitTest来命中列标头,然后将命中的位置从网格坐标转换为屏幕坐标。
public partial class Form1 : Form
{
DataGridView dataGrid;
ContextMenuStrip contextMenuStrip;
public Form1()
{
InitializeComponent();
dataGrid = new DataGridView();
Controls.Add(dataGrid);
dataGrid.Dock = System.Windows.Forms.DockStyle.Fill;
//dataGrid.ColumnHeaderMouseClick += ColumnHeaderMouseClick;
dataGrid.MouseDown += MouseDown;
dataGrid.DataSource = new Dictionary<string, string>().ToList();
contextMenuStrip = new ContextMenuStrip();
contextMenuStrip.Items.Add("foo");
contextMenuStrip.Items.Add("bar");
}
private void ColumnHeaderMouseClick(object sender, DataGridViewCellMouseEventArgs e)
{
if (e.Button == System.Windows.Forms.MouseButtons.Right)
{
contextMenuStrip.Show(PointToScreen(e.Location));
}
}
private void MouseDown(object sender, MouseEventArgs e)
{
if (e.Button == System.Windows.Forms.MouseButtons.Right)
{
if (dataGrid.HitTest(e.X, e.Y).Type == DataGridViewHitTestType.ColumnHeader)
{
contextMenuStrip.Show(dataGrid.PointToScreen(e.Location));
}
}
}
}
你差一点就对了。您只需要将PointToScreen
方法应用于调用控件:
private void ColumnHeaderMouseClick(object sender, DataGridViewCellMouseEventArgs e)
{
if (e.Button == System.Windows.Forms.MouseButtons.Right)
{
contextMenuStrip.Show(((DataGridView)sender).PointToScreen(e.Location));
}
}
我认为这是最优雅的解决方案,因为它只使用ColumnHeaderMouseClick
参数而不是Cursor.Position
。