Linq语句来获取不是较长字符串的子字符串的字符串

本文关键字：字符串 语句 获取 Linq | 更新日期: 2023-09-27 18:16:19

我有一个长字符串S，可能包含模式p1, p2, p3, ....;

所有图案都放在MatchCollection对象中

我想做一些类似的事情

string ret=p_n if !(S.Contains(p_n))

我写了一个for循环来做这个

foreach(string p in PatternList)
{
   s=(!S.contain(p.valus))?p.value:"";
}

我想知道一个LINQ声明，让我的代码更可爱。

Linq语句来获取不是较长字符串的子字符串的字符串

var patterns = new List<string> { "one", "two", "three" };
var misses = patterns.Where(s => !longString.Contains(s)); 

class Program
{
    static void Main(string[] args)
    {
        string S = "12345asdfasdf12w3e412354w12341523142341235123";
        string patternString = "one1234554321asdf";

        MatchCollection p_ns = Regex.Matches(patternString, "one|12345|54321|asdf");
        var nonMatches = (from p_n in p_ns.Cast<Match>()
                          where !S.Contains(p_n.Value)
                          select p_n.Value);
        foreach (string nonMatch in nonMatches)
        {
            Console.WriteLine(nonMatch);
        }
        Console.ReadKey();
    }
}

或者，要使用贾斯汀的答案，你也可以使用下面的变体。

class Program
{
    static void Main(string[] args)
    {
        string S = "12345asdfasdf12w3e412354w12341523142341235123";
        string patternString = "one1234554321asdf";

        MatchCollection p_ns = Regex.Matches(patternString, "one|12345|54321|asdf");
        var nonMatches = p_ns.Cast<Match>().Where(s => !S.Contains(s.Value));
        foreach (Match nonMatch in nonMatches)
        {
            Console.WriteLine(nonMatch.Value);
        }

        Console.ReadKey();
    }
}

    static void Main(string[] args)
    {
        string S = "p1, p2, p3, p4, p5, p6";
        List<string> PatternList = new List<string>();
        PatternList.Add("p2");
        PatternList.Add("p5");
        PatternList.Add("p9");
        foreach (string s in PatternList.Where(x => !S.Contains(x)))
        {
            Console.WriteLine(s);
        }
        Console.ReadKey();
    }
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