用抽象类序列化c# XML

本文关键字:XML 序列化 抽象类 | 更新日期: 2023-09-27 18:16:23

我目前正在尝试将一些命令设置为通信协议序列化的类。我的代码基本如下:

[XmlRoot("Message")]
[Serializable]
public class Message
{
    private Command[] _commands;
    [XmlAttribute("ver")]
    public int Version { get; set; }
    [XmlAttribute("msid")]
    public Guid Id { get; set; }
    [XmlArray("Commands")]
    [XmlArrayItem(typeof(HealthCheckCommand))]
    [XmlArrayItem(typeof(TestCommand))]
    public Command[] Commands
    {
        get { return _commands; }
        set { _commands = value; }
    }
}
public enum CommandTypes
{
    healthcheck
}
[XmlType(TypeName = "Command")]
public abstract class Command
{
    String CommandType { get; set; }
}
public class HealthCheckCommand : Command
{
    [XmlAttribute("type")]
    public string CommandType
    {
        get { return "healthcheck"; }
        set { throw new NotImplementedException(); }
    }
}
public class TestCommand : Command
{
    [XmlAttribute("type")]
    public string CommandType
    {
        get { return "test"; }
        set { throw new NotImplementedException(); }
    }
}

我需要得到的是:

<Message ver="1" msid="00000000-0000-0000-0000-000000000000">
  <Commands>
    <Command type="healthcheck" />
    <Command type="test" />
  </Commands>
</Message>

我得到的是:

<Message ver="1" msid="00000000-0000-0000-0000-000000000000">
  <Commands>
    <HealthCheckCommand type="healthcheck" />
    <TestCommand type="test" />
  </Commands>
</CTM>

当我尝试用相同的名称覆盖XmlArrayItem名称时,它当然会抛出错误。如果我使用列表,那么它可以工作,但是我在子类型中得到了所有名称空间的东西,这是我不想要的。我可以在事后删除这些名称空间项,但我不想这样做。一定有办法的。

谢谢你的帮助!

编辑:

序列化代码:

XmlSerializer serializer = new XmlSerializer(typeof (Message));
        using (TextWriter writer = new StreamWriter(@"C:'Xml.txt"))
        {
            XmlSerializerNamespaces xmlSerializerNamespaces = new XmlSerializerNamespaces();
            xmlSerializerNamespaces.Add("", "");
            XmlWriterSettings settings = new XmlWriterSettings();
            settings.OmitXmlDeclaration = true;
            using (
            XmlWriter xmlwriter = XmlWriter.Create(writer, new XmlWriterSettings { OmitXmlDeclaration = true }))
            {
                serializer.Serialize(xmlwriter, message, xmlSerializerNamespaces);
            }
        }
    }

用抽象类序列化c# XML

通过将相关的XmlInclude属性添加到Message来包含派生类型:

[XmlInclude(typeof(HealthCheckCommand))]
[XmlInclude(typeof(TestCommand))]

然后为您的Command[]数组项指定元素名称:

[XmlArrayItem("Command")]

这会创建像这样的XML,这可能与使用List时相同:

<Message xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" ver="0" msid="00000000-0000-0000-0000-000000000000">
    <Commands>
        <Command xsi:type="HealthCheckCommand" type="healthcheck" />
        <Command xsi:type="TestCommand" type="test" />
    </Commands>
</Message>

不幸的是,xsi:type属性是反序列化工作所必需的(否则序列化程序如何知道使用哪种类型?)不过,这些可以很容易地在事后删除。使用XDocument解析XML并删除它们,如下所示:

XNamespace xsi = "http://www.w3.org/2001/XMLSchema-instance";
doc.Descendants()
   .Attributes(xsi + "type")
   .Remove();
doc.Descendants()
   .Attributes()
   .Where(a => a.IsNamespaceDeclaration && a.Value == xsi)
   .Remove();