选择不同于多个表linq到sql

本文关键字:linq sql 不同于 选择 | 更新日期: 2023-09-27 18:16:27

我有两个表,tblItem和tblInsertLines,在tblInsertLines中,我有相同的ItemId,但有不同的ProdDate和ExpireDate,我想获得所有项目的不同列表,但选择第一行从tblInsertLines作为第一行包含最古老的ProdDate。任何帮助都将不胜感激。我使用这个代码。

public static List<Item> getItemList()
    {
        using (var db = new AWarehouseDataClassesDataContext())
        {
            var list = (from i in db.tblItems
                        join e in db.tblInsertLines on i.ItemId equals e.ItemId 
                        orderby i.NameE
                        select new Item
                        {
                            code = i.Code,
                            itemId = i.ItemId,
                            lastUpdate = i.LastUpdate,
                            nameA = i.NameA,
                            nameE = i.NameE,
                            qty = i.Qty,
                            prodDate = e.ProdDate,
                            expireDate = e.ExpireDate,
                            updatedBy = i.UpdatedBy
                        }).Distinct();
            return list.ToList();
        }
    }

选择不同于多个表linq到sql

你可以试试

    var list= (from i in db.tblItems
                join e in db.tblInsertLines on i.ItemId equals e.ItemId 
                where e.counter > 0
                orderby i.NameE
                group new { i, e } by e.ItemId into g
                select new Item
                {
                    code = g.First().i.Code,
                    itemId = g.Key,
                    lastUpdate = g.First().i.LastUpdate,
                    nameA = g.First().i.NameA,
                    nameE = g.First().i.NameE,
                    qty = g.First().i.Qty,
                    prodDate = g.Min(x=>x.e.ProdDate),
                    expireDate = g.First().e.ExpireDate,
                    updatedBy = g.First().i.UpdatedBy
                }).ToList();