创建JSON文件格式c#

我需要创建以下格式的JSON文件:

"Result": [
         [ "Date", "Name", "Address", "Age" ],
         [ "MMDDYYYY", "Name1", "Add1", "15" ],
         [ "MMDDYYYY", "Name2", "Add2", "20" ]

结果的数据是由DataTable填充的List<string>填充的List<JArray>，如下所示:

var jArrayList = new List<JArray>();
var rowData = new List<string>();
for (int i = 0; i < table.Rows.Count; i++)
{
   var rowData = new List<string>(table.Columns.Count);
   DataRow dataRow = table.Rows[i];
   foreach (DataColumn dataColumn in table.Columns)
   {
      if (i > 0)
      {
         rowData.Add(dataRow[dataColumn].ToString());
      }
    }
    if (rowData.Any())
    {
       jArrayList.Add(new JArray(rowData));
    }
 }
 if (jArrayList.Any())
 {
    var jobj = new JObject( new JProperty("Result",
                            from p in jArrayList
                            select p));
     jObjList.Add(jobj);
  }
  var outputJson = new JObject(new JProperty("Entries",
                                        from p in jObjList
                                        select p));
  var outputString = outputJson.ToString();

当我执行这段代码时，它将所有内容写入新行:

"Result": [
    [
      "Date",
      "Name",
      "Address",
      "Age"
    ],
    [
      "MMDDYYYY",
      "Name1",
      "Add1",
      "15"
    ],
    [
      "MMDDYYYY",
      "Name2",
      "Add2",
      "20"
    ],

如何格式化以这种方式编写?

"Result": [
     [ "Date", "Name", "Address", "Age" ],
     [ "MMDDYYYY", "Name1", "Add1", "15" ],
     [ "MMDDYYYY", "Name2", "Add2", "20" ]

string json = "'"Result'": ['r'n    ['r'n      '"Date'",'r'n      '"Name'",'r'n      '"Address'",'r'n      '"Age'"'r'n    ],'r'n    ['r'n      '"MMDDYYYY'",'r'n      '"Name1'",'r'n      '"Add1'",'r'n      '"15'"'r'n    ],'r'n    ['r'n      '"MMDDYYYY'",'r'n      '"Name2'",'r'n      '"Add2'",'r'n      '"20'"'r'n    ],";
            var withoutEnter = json.Replace(Environment.NewLine, "");
            var splited = withoutEnter.Split('[');
            var formattedJson = splited[0];
            for (int i = 1; i < splited.Length; i++)
            {
                formattedJson = formattedJson + "[" + splited[i] + "'n";
            }