HttpClient:如何一次上传多个文件

本文关键字：文件 何一次 HttpClient | 更新日期: 2023-09-27 18:16:43

我正在尝试使用System.Net.Http.HttpClient上传多个文件。

using (var content = new MultipartFormDataContent())
{
   content.Add(new StreamContent(imageStream), "image", "image.jpg");
   content.Add(new StreamContent(signatureStream), "signature", "image.jpg.sig");
   var response = await httpClient.PostAsync(_profileImageUploadUri, content);
   response.EnsureSuccessStatusCode();
}

这只发送多部分/表单数据，但我期望在帖子的某个地方多部分/混合。

更新:好吧，我得到了。

using (var content = new MultipartFormDataContent())
{
    var mixed = new MultipartContent("mixed")
    {
        CreateFileContent(imageStream, "image.jpg", "image/jpeg"),
        CreateFileContent(signatureStream, "image.jpg.sig", "application/octet-stream")
    };
    content.Add(mixed, "files");
    var response = await httpClient.PostAsync(_profileImageUploadUri, content);
    response.EnsureSuccessStatusCode();
}
private StreamContent CreateFileContent(Stream stream, string fileName, string contentType)
{
    var fileContent = new StreamContent(stream);
    fileContent.Headers.ContentDisposition = new ContentDispositionHeaderValue("file") {FileName = fileName};
    fileContent.Headers.ContentType = new MediaTypeHeaderValue(contentType);
    return fileContent;
}

这看起来对wire shark是正确的。但是我没有看到我的控制器中的文件。

[HttpPost]
public ActionResult UploadProfileImage(IEnumerable<HttpPostedFileBase> postedFiles)
{
    if(postedFiles == null)
        return new HttpStatusCodeResult(HttpStatusCode.BadRequest);
    // more code here
}

postedFiles仍然为空。什么好主意吗?

HttpClient:如何一次上传多个文件

成功了。但行为却很奇怪。

using (var content = new MultipartFormDataContent())
{
    content.Add(CreateFileContent(imageStream, "image.jpg", "image/jpeg"));
    content.Add(CreateFileContent(signatureStream, "image.jpg.sig", "application/octet-stream"));
    var response = await httpClient.PostAsync(_profileImageUploadUri, content);
    response.EnsureSuccessStatusCode();
}
private StreamContent CreateFileContent(Stream stream, string fileName, string contentType)
{
    var fileContent = new StreamContent(stream);
    fileContent.Headers.ContentDisposition = new ContentDispositionHeaderValue("form-data") 
    { 
        Name = "'"files'"", 
        FileName = "'"" + fileName + "'""
    }; // the extra quotes are key here
    fileContent.Headers.ContentType = new MediaTypeHeaderValue(contentType);            
    return fileContent;
}
[HttpPost]
public ActionResult UploadProfileImage(IList<HttpPostedFileBase> files)
{
    if(files == null || files.Count != 2)
        return new HttpStatusCodeResult(HttpStatusCode.BadRequest);
    // more code
}
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