执行ms-access查询时出错

本文关键字：出错 查询 ms-access 执行 | 更新日期: 2023-09-27 18:17:04

我创建了一个查询，在c#中一次插入两个ms访问表。我得到了异常

{System.Data.OleDb。oledbeexception:在SQL结束后发现字符声明。在System.Data.OleDb.OleDbCommand.ExecuteCommandTextErrorHandling (OleDbHResult人力资源)System.Data.OleDb.OleDbCommand.ExecuteCommandTextForSingleResult (tagDBPARAMSdbParams Object&executeResult)System.Data.OleDb.OleDbCommand.ExecuteCommandText (Object&executeResult)System.Data.OleDb.OleDbCommand.ExecuteCommand (CommandBehavior行为,Object&executeResult)System.Data.OleDb.OleDbCommand.ExecuteReaderInternal (CommandBehavior行为，字符串方法)System.Data.OleDb.OleDbCommand.ExecuteNonQuery ()CompanyDetails.Model.CompanyDetailsModel.setCompanyDetailsToDB (CompanyDetailsDataList_cmpDetailsList) in E:'Project'PBAttendence' modifyprivilege 'CompanyDetails'Model'CompanyDetailsModel.cs:line62}

我的示例代码如下，请解决我的问题。对不起，我的英语不好。

int companyID = _cmpDetailsList[0].CompanyID;
                    string companyName = _cmpDetailsList[0].CompanyName;
                    string contactID = _cmpDetailsList[0].ContactID;
                    string companyAddress = _cmpDetailsList[0].CompanyAddress;
                    if (companyID == -1)
                    {
                        OleDbCommand cmd = new OleDbCommand("Insert into CompanyDetails([CompanyName],[CompanyAddress],[ContactID]) values ('" + companyName + "','" + companyAddress + "','" + contactID + "');Insert into UserCompanyDetails([UserID],[CompanyID]) values (" + "Select [UserID] from UserDetails;" + "," + "Select @@identity;" + "); ", conn);
                        conn.Open();
                        cmd.ExecuteNonQuery();
                        conn.Close();
                    }
                    else
                    {
                        OleDbCommand upcmd = new OleDbCommand("update CompanyDetails set [CompanyName] = '" + companyName + "',[CompanyAddress] = '" + companyAddress + "',[ContactID] = '" + contactID + "' where [CompanyID] = @cmpID;", conn);
                        conn.Open();
                        upcmd.Parameters.AddWithValue("@cmpID", companyID);
                        upcmd.ExecuteNonQuery();
                        conn.Close();
                    }

现在我分裂成两个插入命令，但我得到了错误{System.Data.OleDb。oledbeexception:语法错误。Select [UserID] from UserDetails;

OleDbCommand cmd = new OleDbCommand("Insert into CompanyDetails([CompanyName],[CompanyAddress],[ContactID]) values ('" + companyName + "','" + companyAddress + "','" + contactID + "');", conn);
                        conn.Open();
                        cmd.ExecuteNonQuery();
                        conn.Close();
                        OleDbCommand cmd1 = new OleDbCommand("Insert into UserCompanyDetails([UserID],[CompanyID]) values (" + "Select [UserID] from UserDetails;" + "," + "Select @@identity" + ");", conn);
                        conn.Open();
                        cmd1.ExecuteNonQuery();
                        conn.Close();

执行ms-access查询时出错

问题是这行代码:

OleDbCommand cmd = new OleDbCommand("Insert into CompanyDetails([CompanyName],[CompanyAddress],[ContactID]) values ('" + companyName + "','" + companyAddress + "','" + contactID + "');Insert into UserCompanyDetails([UserID],[CompanyID]) values (" + "Select [UserID] from UserDetails;" + "," + "Select @@identity;" + "); ", conn);

在同一个OleDbCommand中有两个insert语句。试着将它移动到两个不同的步骤中:

  1. 插入CompanyDetails表
  2. 插入UserCompanyDetails表

希望这对你有帮助

首先，使用原始sql命令比使用代码生成sql更容易。
您可能会考虑创建一个存储过程，因为您的命令变得有点复杂
如果我是正确的，你目前要做的是:

Insert into table1(x,y,z) values a,b,c;
Insert into table2(x,y) values select * from table3; , @@identity

第二个sql命令在语法和逻辑上都是无效的，您的@@身份将不是静态的，因为您在命令期间插入新记录。
我的建议是这样做:

Insert into table1(x,y,z) values a,b,c;
declare @table1Id int = @@identity
Insert into table2(x,y) select colA, @table1Id from table3;

你不能有;Access中的查询。请参阅http://office.microsoft.com/en-us/access-help/HV080760224.aspx您必须按照@juanreyesv

的建议分别执行两次插入。

你将不得不做3个查询，

    使用sql: "Insert into CompanyDetails([CompanyName],[CompanyAddress],[ContactID]) values ('" + companyName + "','" + companyAddress + "','" + contactID + "') 执行插入
  1. 获取@@身份使用Select @@identity并将其存储在变量idnt
    2. 中
  2. 使用2中获取的identity值。执行第三次插入:"Insert into UserCompanyDetails([UserID],[CompanyID]) Select UserID, " + idnt.ToString() + " from UserDetails"

参考http://msdn.microsoft.com/en-us/library/ks9f57t0%28VS.71%29.aspx

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