我有一个逗号分隔的字符串，我想在c#中使用Regex找到一个特定的字段

本文关键字：字段 一个 Regex 分隔 有一个 字符串 | 更新日期: 2023-09-27 18:17:55

这是我的字符串:

"0949418001","12/12/2011","12/21/2011","0010043309","EFT  ","Net 10 Days From Ship Date","","","FOB Origin/Collect","","","0000835369","DUPRE TRANSPORTS INC","DUPR      ","0231653047","1/23/2012","Motor Fuel Dest","1049930","8784.00","8796.00","8784.00","UG6  ","N","0.196500","1726.06","25405.51","TAX ","REG","","PASADENA,TX,COP,RFYC (03FV)","   ","0000835369","835369","1726.06","01/23/2012","0.00","23679.45"

我想使用正则表达式获得单词"Motot Fuel Dest"前面的日期。我们怎么才能得到呢?

我有一个逗号分隔的字符串，我想在c#中使用Regex找到一个特定的字段

可以这样写…

/(?<=")[^"]+(?=","Motor Fuel Dest)/

根据您的正则表达式风格，语法可能会有所不同。

编辑:.NET版本的解决方案

resultString = Regex.Match(subjectString, "(?<='")[^'"]+(?='",'"Motor Fuel Dest)").Value;

这不是什么特别的东西，只是向后看/向前看，只捕捉你需要的

这也可以…

var dateMatch = Regex.Match(myInputString, @"(?<Date>'d{1,2}/'d{1,2}/'d{4})"",Motor'sFuel'sDest");
DateTime theValue = DateTime.Parse(dateMatch.Groups["Date"].Value);

那么在theValue字段中，您有作为DateTime的值。

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