C# 用两个随机数求和,但它必须等于用户输入

本文关键字:于用户 输入 用户 两个 随机数 求和 | 更新日期: 2023-09-27 18:18:33

我想知道是否可以从用户输入 int 中得出总和,但每次总和都必须是 radom。

这是我制作的代码:

    public static string genSum(int askedNumber)
    {
        string outputStr = null;
        bool switchOneTwo = false;
        int neededSum = 0;
        int intOne = 0;
        int intTwo = 0;
        while (askedNumber != neededSum)
        {
            if (switchOneTwo == true)
            {
                intOne += 1;
                switchOneTwo = false;
            }
            else
            {
                intTwo += 1;
                switchOneTwo = true;
            }
            neededSum = intOne + intTwo;
            if (neededSum == askedNumber)
            {
                if (neededSum >= 4)
                {
                    Random randomInt = new Random();
                    int tmpIntOne = intOne;
                    int tmpIntTwo = intTwo;
                    int method;
                    //For now only one method
                    method = randomInt.Next(1, 1);
                    if (method == 1)
                    {
                        tmpIntOne = tmpIntOne / 2;
                        tmpIntTwo = (tmpIntTwo * 2) - tmpIntOne;
                    }
                    intOne = tmpIntOne;
                    intTwo = tmpIntTwo;                
                }
                outputStr = "(" + intOne.ToString() + "+" + intTwo.ToString() + ")";
                return outputStr;
            }
        }
        return outputStr;
    }

所以我想要的是,如果用户输入一个数字,例如 20,它将产生一个总和:

用户输入 20 并按 GO!

结果:

10 + 10 = 20

12 + 8 = 20

5 + 15 = 20

1 + 19 = 20

3 + 17 = 20

用户输入 500 并按 GO!

结果:

9 + 491 = 500

263 + 237 = 500

300 + 200 = 500

250 + 250 = 500

109 + 391 = 500

C# 用两个随机数求和,但它必须等于用户输入

创建一个小于输入的随机数,另一个将是User-YourRandom

void Foo(int userNumber)
{
    Random r = new Random();
    int firstNumber = r.Next(userNumber - 1);
    int secondNumber = userNumber - firstNumber;
}

您也可以将其扩展为支持负数。

编辑获取真实随机数

正如 I4V 指出的那样,如果将其放在循环中,您可能会得到相同的一组数字,因此您可以使用此方法而不是调用Random

void Foo(int userNumber)
{
    int userNumber = 500;
    for (int i = 0; i < 10; i++ )
    {
        int firstNumber = Next(0, userNumber - 1);
        int secondNumber = userNumber - firstNumber;
        Console.WriteLine(firstNumber + "+" + secondNumber);
    }
}
internal static int RandomExt(int min, int max)
{
    RNGCryptoServiceProvider rng = new RNGCryptoServiceProvider();
    byte[] buffer = new byte[4];
    rng.GetBytes(buffer);
    int result = BitConverter.ToInt32(buffer, 0);
    return new Random(result).Next(min, max);
}
foreach (var s in genSum(500).Take(5))
{
    Console.WriteLine(s);
}

public static IEnumerable<string> genSum(int askedNumber)
{
    Random r = new Random();
    while (true)
    {
        var i = r.Next(0, askedNumber);
        yield return i + "+" + (askedNumber - i);
    }
}