使用递归属性 ASP.NET / C#
本文关键字:NET ASP 属性 递归 | 更新日期: 2023-09-27 17:53:32
我正在寻找一种方法来获取通用结果集,并使用jQuery Dyantree将其转换为具有 ASP.NET MVC的树结构。我有一个测试类,例如:
public class GenericResults
{
public string ClaimId { get; set; }
public string DrugName { get; set; }
public int PatientId { get; set; }
//simulates database call, this could be any type of result set
public static List<GenericResults> MockDatabaseCall()
{
return new List<GenericResults>()
{
new GenericResults { ClaimId = "abc", DrugName="Drug 1", PatientId=1 },
new GenericResults { ClaimId = "bcd", DrugName="Drug 2", PatientId=1 },
new GenericResults { ClaimId = "def", DrugName="Drug 3", PatientId=1 },
new GenericResults { ClaimId = "fgi", DrugName="Drug 4", PatientId=1 },
new GenericResults { ClaimId = "ijk", DrugName="Drug 5", PatientId=2 },
new GenericResults { ClaimId = "klm", DrugName="Drug 6", PatientId=2 },
new GenericResults { ClaimId = "mno", DrugName="Drug 7", PatientId=2 },
new GenericResults { ClaimId = "pqr", DrugName="Drug 8", PatientId=2 },
new GenericResults { ClaimId = "qrs", DrugName="Drug 9", PatientId=2 },
new GenericResults { ClaimId = "stu", DrugName="Drug 10", PatientId=2 },
};
}
}
Dynatree的数据需要的结构是这样的:
public string Title { get; set; }
public List<TreeView> Children { get; set; }
public bool IsFolder
{
get
{
return this.Children.Count > 0;
}
}
在此示例中,我们确实不需要 ClaimId
属性,但我想重用我已经编写的存储过程来馈送到树,因此我想包含它。我需要已分组的内容成为其自己的TreeView
对象,并且Children
属性是具有分组内容值的所有记录。 到目前为止,MockDatabaseCallMethod
,如果我分组PatientId
我将需要两个TreeView
对象:每个唯一的PatientId一个。 我希望能够以递归方式执行此操作,但不确定如何,因为某些项目将是叶子(没有子项(,这很好。 这是我的尝试:
public class TreeView
{
public string Title
{
get;
set;
}
public List<TreeView> Children { get; set; }
public bool IsFolder
{
get
{
return this.Children.Count > 0;
}
}
//made void for the time being to limit compilation errors
public static void ListToTree(string displayName,string groupedOn)
{
//seed data
List<GenericResults> results = GenericResults.MockDatabaseCall();
//"group" on the property passed by the user
var query = results.Select(x => x.GetType().GetProperty(groupedOn).GetValue(x,null)).Distinct();
foreach (var i in query)
{
var treeView = new TreeView();
treeView.Title = displayName;
//iterate over results, if object has the property value of what's currently being iterated over
//create a new TreeView object for it
treeView.Children = results.Where(x => x.GetType().GetProperty(groupedOn).GetValue(x, null) == i)
.Select(n => new TreeView
{
Title = displayName,
Children = x <--no idea what to do here
});
}
}
}
理想情况下,我想要一个ToTree
扩展方法,但起初我想得到一些关于此的指示。 谢谢:)
我不确定我是否正确理解了你,但如果我理解正确,我会建议以下解决方案:
-(在TreeView
将属性public List<TreeView> Children { get; set; }
更改为public IEnumerable<GenericResults> Children { get; set; }
。
-(将void ListToTree(string displayName
方法替换为以下方法:
public static List<TreeView> ListToTree(string displayName, string groupedOn)
{
//seed data
List<GenericResults> results = GenericResults.MockDatabaseCall();
List<TreeView> trees = new List<TreeView>();
//"group" on the property passed by the user
var query = results.Select(x => x.GetType().GetProperty(groupedOn).GetValue(x, null)).Distinct();
foreach (int i in query)
{
var treeView = new TreeView();
treeView.Title = displayName;
treeView.Children = results.Where(x => ((int)x.GetType().GetProperty(groupedOn).GetValue(x, null)) == i);
trees.Add(treeView);
}
return trees;
}
但是,我不确定,如果我正确理解了您;-(