已在 SQL 中求和的列的总和

本文关键字：和的 SQL 求和 已在 | 更新日期: 2023-09-27 18:23:35

SELECT DISTINCT emp_no, sum(CASE WHEN isnull(PresAbs,0)='WO' THEN 1 ELSE 0 END)  WO,
    sum(CASE WHEN isnull(PresAbs,0)='WP' THEN 1 ELSE 0 END)  WP, 
sum(CASE WHEN isnull(PresAbs,0)='HL' THEN 1 ELSE 0 END)  HL, 
sum(CASE WHEN isnull(PresAbs,0)='A' THEN 1 ELSE 0 END)  A,**sum(WO+WP+HL+A)** 
from TRN_ATTN072013 WHERE CONVERT(varchar,Tdate,112)>'20130712' and CONVERT(varchar,Tdate,112)<'20130717' 
group by emp_no
ORDER BY emp_no

我想总结一下这些列 WO，WP，HL，A 我如何对这些列求和

已在 SQL 中求和的列的总和

如果这是SQL server那么您可以使用CTE 

with tablesum as
(
  SELECT DISTINCT emp_no, sum(CASE WHEN isnull(PresAbs,0)='WO' THEN 1 ELSE 0 END)  WO,
                          sum(CASE WHEN isnull(PresAbs,0)='WP' THEN 1 ELSE 0 END)  WP,
                          sum(CASE WHEN isnull(PresAbs,0)='HL' THEN 1 ELSE 0 END)  HL,
                          sum(CASE WHEN isnull(PresAbs,0)='A' THEN 1 ELSE 0 END)  A
  from TRN_ATTN072013 
  WHERE CONVERT(varchar,Tdate,112) > '20130712' and CONVERT(varchar,Tdate,112) < '20130717'
  group by emp_no      
)
select t.*, t.WO + t.WP + t.HL + t.A
from tablesum t
order by t.emp_no

in mysql ;)

SELECT emp_no, wo+wp+hl+A FROM 
(SELECT DISTINCT emp_no, sum(CASE WHEN isnull(PresAbs,0)='WO' THEN 1 ELSE 0 END)  WO,
sum(CASE WHEN isnull(PresAbs,0)='WP' THEN 1 ELSE 0 END)  WP, 
sum(CASE WHEN isnull(PresAbs,0)='HL' THEN 1 ELSE 0 END)  HL, 
sum(CASE WHEN isnull(PresAbs,0)='A' THEN 1 ELSE 0 END)  A,**sum(WO+WP+HL+A)** 
from TRN_ATTN072013 WHERE CONVERT(varchar,Tdate,112)>'20130712' and   CONVERT(varchar,Tdate,112)<'20130717' 
group by emp_no
ORDER BY emp_no) AS SUB_Q;
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