读取字符串中的字符串

本文关键字：字符串 读取 | 更新日期: 2023-09-27 18:24:34

如果你有这个：

foreach(string n in txtList)
{
    Console.WriteLine(n);
}

输出：

[HKEY_Something_Something'.abc]
[HKEY_Something_Something'.defg]
[HKEY_Something_Something'.ijklmn]

如何获取介于"."answers"]"之间的内容？

读取字符串中的字符串

如果它总是遵循这种格式，那么将代码更改为这种格式应该会输出您想要的内容：

foreach(string n in txtList)
{
  int startindex = n.IndexOf(@"'.") + 2;
  Console.WriteLine(n.Substring( startindex, n.Length-startindex-1));
}

尝试

 foreach(string n in txtList)
    {
        string str[] = n.Split('.');
        if (str.Length > 0)
        {
            string s = str[str.Length-1];
            Console.WriteLine(s.Substring(0, s.Length-1));
        }
    }

您可以使用正则表达式：

var s = @"[HKEY_Something_Something'.abc]";
var result = Regex.Match(s, @"(?<='.)[^]]*(?=]$)")
// result == "abc"

正则表达式的简短解释：

(?<='.) - preceded by a dot
[^]]*   - anything which isn't a ']'
(?=]$)  - followed by a ']' and the end of the string

var per = n.IndexOf("."); // may need to add +1 to get past . index.
var len = n.IndexOf("]") - per - 1;
var val = n.Substring(per, len);

简单答案：

int dotPosition = n.LastIndexOf(".") + 1; // +1 because we start AFTER the dot.
int bracketPosition = n.LastIndexOf("]"); // can do "n.Length - 2" too.
Console.WriteLine(n.Substring(dotPosition, bracketPosition - dotPosition));

更复杂的答案是：使用正则表达式。

例如RegEx:

  Match match = Regex.Match(n, @"'.(.*)']");  
  string result = match.Groups[1].Value;
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