在mvc中一次保存多个视图的模型数据

本文关键字：视图 数据 模型 保存 一次 mvc | 更新日期: 2023-09-27 18:25:07

我有5个类：

1） EmployeeMainTable.cs（Employeeid是主键，Employeeid是类其余部分的外键）

2） EmployeeFamilyTable.cs

3） 以前的工作.cs

4） employeeaddress.cs

5） employeeEducation.cs

每个类包含各自的属性在此处输入代码

现在我想为每个类做的是，我已经创建了5个视图来输入数据，每个视图都包含提交按钮以转到下一个视图

我的问题是，当我在最后一个视图中单击完成按钮时，我想一次保存所有模型。

请理解问题一次我使用mvc 4

我尝试过以下结果：

@model SecondStep
@using(Html.BeginForm("ThirdStep", "controllerName", FormMethod.Post))
{ 
    @Html.HiddenFor(model => ViewBag.FirstStepModel.Value) 
    @Html.EditorFor(model => model.Value)
    <input type="submit" value="Next"/>
}

CS1963: An expression tree may not contain a dynamic operation

中出现错误

@Html.HiddenFor(model => ViewBag.FirstStepModel.Value)
Line 13: { 
Line 14:
Line 15: @Html.HiddenFor(model=>ViewBag.FirstStepModel) this line giving error 
Line 16: @Html.EditorFor(model => model.SecondStepProp) 
Line 17:

在mvc中一次保存多个视图的模型数据

您应该将以前的视图模型长时间传递到"下一个"视图，因此当单击"完成"按钮时，您可以检索所有要在最后创建的模型（在控制器中）。（别忘了把你的模型放在帖子里）

更新1:

为什么您需要在控制器上使用GET和POST方法？

USPDATE2：示例

**案例1：如果您有多个视图模型**

控制器

[HttpGet]
public ActionResult FirstStep()
{
    return View(new FirstStepModel());
}
[HttpPost]
public ActionResult SecondStep(FirstStepModel firstStepModel)
{
    ViewBag.FirstStepModel = firstStepModel;
    return View(new SecondStepModel());
}
[HttpPost]
public ActionResult ThridStep(FirstStepModel firstStepModel, SecondStepModel secondStepModel)
{
    ViewBag.FirstStepModel = firstStepModel;
    ViewBag.SecondStepModel = secondStepModel;
    return View(new ThirdStepModel());
}
[HttpPost]
public ActionResult FourthStep(FirstStepModel firstStepModel, SecondStepModel secondStepModel, ThirdStepModel thirdStepModel)
{
    ViewBag.FirstStepModel = firstStepModel;
    ViewBag.SecondStepModel = secondStepModel;
    ViewBag.ThirdStepModel = thirdStepModel;
    return View(new FourthStepModel()));
}
[HttpPost]
public ActionResult FifthStep(FirstStepModel firstStepModel, SecondStepModel secondStepModel, ThirdStepModel thirdStepModel, FourthStepModel fourthStepModel)
{
    ViewBag.FirstStepModel = firstStepModel;
    ViewBag.SecondStepModel = secondStepModel;
    ViewBag.ThirdStepModel = thirdStepModel;
    ViewBag.FourthStepModel = fourthStepModel;
    return View(new FinalStepModel());
}
[HttpPost]
public ActionRestul Finish(FirstStepModel firstStepModel, SecondStepModel secondStepModel, ThirdStepModel thirdStepModel, FourthStepModel fourthStepModel, FifthStepModel fifthStepModel)
{
    // DB Save ?
}

视图第一步：

@model FirstStep
@using(Html.BeginForm("SecondStep", "controllerName", FormMethod.Post))
{
    @Html.EditorFor(model => model.Value)
    <input type="submit" value="Next"/>
}

第二步：

@model SecondStep
@using(Html.BeginForm("ThirdStep", "controllerName", FormMethod.Post))
{ 
    @Html.HiddenFor(model => ViewBag.FirstStepModel.Value) 
    @Html.EditorFor(model => model.Value)
    <input type="submit" value="Next"/>
}

第三步：

@model ThirdStep
@using(Html.BeginForm("FourthStep", "controllerName", FormMethod.Post))
{  
    @Html.HiddenFor(model => ViewBag.FirstStepModel.Value) 
    @Html.HiddenFor(model => ViewBag.SecondStepModel.Value) 
    @Html.EditorFor(model => model.Value)
    <input type="submit" value="Next"/>
}

第四步：

@model FourthStep
@using(Html.BeginForm("FifthStep", "controllerName", FormMethod.Post))
{
    @Html.HiddenFor(model => ViewBag.FirstStepModel.Value) 
    @Html.HiddenFor(model => ViewBag.SecondStepModel.Value) 
    @Html.HiddenFor(model => ViewBag.ThirdStepModel.Value) 
    @Html.EditorFor(model => model.Value)
    <input type="submit" value="Next"/>
}

第五步：

@model FifthStep
@using(Html.BeginForm("Finish", "controllerName", FormMethod.Post))
{
    @Html.HiddenFor(model => ViewBag.FirstStepModel.Value) 
    @Html.HiddenFor(model => ViewBag.SecondStepModel.Value) 
    @Html.HiddenFor(model => ViewBag.ThirdStepModel.Value) 
    @Html.HiddenFor(model => ViewBag.FifthStepModel.Value) 
    @Html.EditorFor(model => model.Value)
    <input type="submit" value="Next"/>
}

案例2：单视图模型小心：要做到这一点，你需要（根据你的模型的复杂性）一个模型的ModelBinder

[HttpGet]
public ActionResult FirstStep()
{
    return View("FirstStep", new Model());
}
[HttpPost]
public ActionResult SecondStep(Model model)
{
    return View("SecondStep", model);
}
[HttpPost]
public ActionResult ThridStep(Model model)
{
    return View("ThirdStep", model);
}
[HttpPost]
public ActionResult Finish(Model model)
{
    // DB Save ?
}

视图

第一步：

@model Model
@using(Html.BeginForm("SecondStep", "controllerName", FormMethod.Post))
{
    @Html.EditorFor(model => model.Step1Value)
    <input type="submit" value="Next"/>
}

第二步：

@model Model
@using(Html.BeginForm("ThirdStep", "controllerName", FormMethod.Post))
{
    @Html.HiddenFor(model => model.Step1Value)
    @Html.EditorFor(model => model.Step2Value)
    <input type="submit" value="Next"/>
}

第三步：

@model Model
@using(Html.BeginForm("Finish", "controllerName", FormMethod.Post))
{
    @Html.HiddenFor(model => model.Step1Value)
    @Html.HiddenFor(model => model.Step2Value)
    @Html.EditorFor(model => model.Step3Value)
    <input type="submit" value="Next"/>
}
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