如何将枚举类型值分配给变量
本文关键字:分配 变量 类型 枚举 | 更新日期: 2023-09-27 18:26:15
我有一些工厂代码,它根据表示枚举的类成员的值创建对象:
public enum BeltPrinterType
{
None,
ZebraQL220,
ONiel
// add more as needed
}
public static BeltPrinterType printerChoice = BeltPrinterType.None;
public class BeltPrinterFactory : IBeltPrinterFactory
{
// http://stackoverflow.com/questions/17955040/how-can-i-return-none-as-a-default-case-from-a-factory?noredirect=1#comment26241733_17955040
public IBeltPrinter NewBeltPrinter()
{
switch (printerChoice)
{
case BeltPrinterType.ZebraQL220:
return new ZebraQL220Printer();
case BeltPrinterType.ONiel:
return new ONielPrinter();
default:
return new None();
}
}
}
在调用NewBeltPinter()之前,我需要设置printerChoice的值,也就是说,如果它已经从默认的"None"值更改。因此,我试图根据字符串表示来分配该值,但这次尝试已经达到了众所周知的不连续点:
string currentPrinter = AppSettings.ReadSettingsVal("beltprinter");
Type type = typeof(PrintUtils.BeltPrinterType);
foreach (FieldInfo field in type.GetFields(BindingFlags.Static | BindingFlags.Public))
{
string display = field.GetValue(null).ToString();
if (currentPrinter == display)
{
//PrintUtils.printerChoice = (type)field.GetValue(null);
PrintUtils.printerChoice = ??? what now ???
break;
}
}
我已经试过了我能想到的一切,但得到的回报只是编译器的不断斥责,这几乎把我误解为一个无赖和一个可怜的流氓。
有人知道我应该用什么来代替问号吗?
你的第二个代码块:
PrintUtils.printerChoice = (PrintUtils.BeltPrinterType)
Enum.Parse(typeof(PrintUtils.BeltPrinterType),
AppSettings.ReadSettingsVal("beltprinter"));
使用Enum.Parse将字符串转换为枚举值。(或者Enum.TryParse,如果它没有解析,则尝试在不引发异常的情况下执行此操作)
编辑
如果您没有可用的Enum.Parse,那么您将不得不自己进行转换:
switch (stringValue)
{
case "BeltPrinterType.ONiel": enumValue = BeltPrinterType.ONiel; break;
...etc...
}
我无法编译到.NET 1.1,但这似乎在2.0 中有效
PrintUtils.printerChoice = (BeltPrinterType)field.GetValue(null);
编辑:我刚刚意识到这基本上是你代码中的一个注释。。。但是,是的,我真的不明白为什么这在1.1 中也不起作用
来自智能设备框架1.x代码库:
public static object Parse(System.Type enumType, string value, bool ignoreCase)
{
//throw an exception on null value
if(value.TrimEnd(' ')=="")
{
throw new ArgumentException("value is either an empty string ('"'") or only contains white space.");
}
else
{
//type must be a derivative of enum
if(enumType.BaseType==Type.GetType("System.Enum"))
{
//remove all spaces
string[] memberNames = value.Replace(" ","").Split(',');
//collect the results
//we are cheating and using a long regardless of the underlying type of the enum
//this is so we can use ordinary operators to add up each value
//I suspect there is a more efficient way of doing this - I will update the code if there is
long returnVal = 0;
//for each of the members, add numerical value to returnVal
foreach(string thisMember in memberNames)
{
//skip this string segment if blank
if(thisMember!="")
{
try
{
if(ignoreCase)
{
returnVal += (long)Convert.ChangeType(enumType.GetField(thisMember, BindingFlags.Public | BindingFlags.Static | BindingFlags.IgnoreCase).GetValue(null),returnVal.GetType(), null);
}
else
{
returnVal += (long)Convert.ChangeType(enumType.GetField(thisMember, BindingFlags.Public | BindingFlags.Static).GetValue(null),returnVal.GetType(), null);
}
}
catch
{
try
{
//try getting the numeric value supplied and converting it
returnVal += (long)Convert.ChangeType(System.Enum.ToObject(enumType, Convert.ChangeType(thisMember, System.Enum.GetUnderlyingType(enumType), null)),typeof(long),null);
}
catch
{
throw new ArgumentException("value is a name, but not one of the named constants defined for the enumeration.");
}
//
}
}
}
//return the total converted back to the correct enum type
return System.Enum.ToObject(enumType, returnVal);
}
else
{
//the type supplied does not derive from enum
throw new ArgumentException("enumType parameter is not an System.Enum");
}
}
}