无法反序列化数组
本文关键字:数组 反序列化 | 更新日期: 2023-09-27 18:26:58
从客户端发送的数据将不会被反序列化。
客户:
$.ajax({
type: 'POST',
dataType: "json",
url: 'savecommentsservice',
data: { "Pid": 0, "Comments": [{ "User": "bbbbbb", "Text": "aaaaaaaa" }, { "User": "ddddddd", "Text": "ccccccccc"}] },
DTO:
public class Comment
{
public string User { get; set; }
public string Text { get; set; }
}
public class SaveCommentsRequest
{
public int Pid { get; set; }
public string SiteId { get; set; }
public string Column { get; set; }
public List<Comment> Comments { get; set; }
}
服务器:
Routes.Add<SaveCommentsRequest>("/savecommentsservice");
...
public object Execute(SaveCommentsRequest request)
{
// Why is request.Comments null !!! All other params of the request works fine
// THe string I'm putting in is generated below - just to make sure its correct
request.Comments = new List<Comment>();
request.Comments.Add(new Comment { Text = "aaaaaaaa", User = "bbbbbb" });
request.Comments.Add(new Comment { Text = "ccccccccc", User = "ddddddd" });
var thisIsWhatIPutInto$AjaxCall = JsonSerializer.SerializeToString<SaveCommentsRequest>(request);
知道怎么了吗?为什么未填充Comments数组。正如您从注释中看到的,我已经使用servicestackjson序列化程序生成了字符串。
也许我在这里错过了一些讨厌的东西?
编辑当看到fiddler发送的内容时,我看到了这个:
POST http://localhost:4920/savecommentsservice HTTP/1.1
Host: localhost:4920
User-Agent: Mozilla/5.0 (Windows NT 5.1; rv:10.0.2) Gecko/20100101 Firefox/10.0.2
Accept: application/json, text/javascript, */*; q=0.01
Accept-Language: zh,en-us;q=0.7,en;q=0.3
Accept-Encoding: gzip, deflate
Connection: keep-alive
Content-Type: application/x-www-form-urlencoded; charset=UTF-8
X-Requested-With: XMLHttpRequest
Referer: http://localhost:4920/default.cshtml?viewId=3
Content-Length: 227
Cookie: ASP.NET_SessionId=slbw453revfgmwuuxyrim1an
Pragma: no-cache
Cache-Control: no-cache
SiteId=Site1&Pid=0&Column=C6&Comments%5B0%5D%5BUser%5D=bbbbbb&Comments%5B0%5D%5BText%5D=aaaaaaaa&Comments%5B1%5D%5BUser%5D=ddddddd&Comments%5B1%5D%5BText%5D=ccccccccc&Comments%5B2%5D%5BUser%5D=ggggggg&Comments%5B2%5D%5BText%5D=
在firebug中:
Parametersapplication/x-www-form-urlencoded
Column C6
Comments[0][Text] aaaaaaaa
Comments[0][User] bbbbbb
Comments[1][Text] ccccccccc
Comments[1][User] ddddddd
Comments[2][Text]
Comments[2][User] ggggggg
Pid 0
SiteId SiteId0
Source
SiteId=SiteId0&Pid=0&Column=C6&Comments%5B0%5D%5BUser%5D=bbbbbb&Comments%5B0%5D%5BText%5D=aaaaaaaa&Comments%5B1%5D%5BUser%5D=ddddddd&Comments%5B1%5D%5BText%5D=ccccccccc&Comments%5B2%5D%5BUser%5D=ggggggg&Comments%5B2%5D%5BText%5D=
问候
Larsi
如您所见,jQuery的Ajax默认将其提交为"application/x-www-form-urlencoded",这是默认的HTML表单发布内容类型。不幸的是,它不能很好地处理嵌套对象,ServiceStack将期望JSV格式的嵌套对象。
因此,对于复杂类型/嵌套对象,您需要告诉jQuery以JSON形式发送请求,您可以通过指定contentType:application/JSON参数来完成,例如:
var data = { "Pid": 0, "Comments": [{ "User": "bbbbbb", "Text": "aaaaaaaa" }]};
$.ajax({
type: 'POST',
dataType: "json",
contentType: "application/json",
url: 'savecommentsservice',
data: JSON.stringify(data)
);
我认为您需要将参数(请求)的名称添加到字符串中。类似…的东西。。
$.ajax({
type: 'POST',
dataType: "json",
url: 'savecommentsservice',
data: {"request": "Pid": 0, "Comments": [{ "User": "bbbbbb", "Text": "aaaaaaaa" }, { "User": "ddddddd", "Text": "ccccccccc"}] },