获取xml数据的属性(wpf c#)

本文关键字：wpf 属性 xml 数据 获取 | 更新日期: 2023-09-27 18:27:19

我有个问题。我想要得到一个元素的属性。我的问题的线索是，所有元素都有相同的名称。

XML数据的外观

<Sampels>
  <Sampel Attribute1="a" Attribute2="b" Attribute3="3" Attribute4="d" />
  <Sampel Attribute1="asdf" Attribute2="b" Attribute3="3" Attribute4="name" />
  <Sampel Attribute1="" Attribute2="" Attribute3="66" Attribute4="attri" />
  <Sampel Attribute1="" Attribute2="b" Attribute3="" Attribute4="sampelname" />
</Sampels>

我想通过知道从Attribute4中指定的正确元素来获得属性。

获取xml数据的属性(wpf c#)

XPath将执行以下操作：

使用这些包括：

using System.Xml.Linq;
using System.Xml.XPath;

并找到您的属性值（xml是您的xml字符串）：

    string search = "sampelname";
    XDocument doc = XDocument.Parse(xml);
    XElement el = doc.XPathSelectElement(string.Format("/Sampels/Sampel[@Attribute4='{0}']", search));

您可以尝试这样的方法。

XElement xmlElement = XElement.Load("myFile.xml");

var attributes = (from e in xmlElement.Elements("Sample")
                  where e.Attribute("Attribute4").Value == "myAtribute4Value"
                  select new {
                      Attribute1 = e.Attribute("Attribute1").Value,
                      Attribute2 = e.Attribute("Attribute2").Value
                  }).FirstOrDefault();

static void Main(string[] main)
{
        var samples = @"<Sampels>
                        <Sampel Attribute1='a' Attribute2='b' Attribute3='3' Attribute4='d' />
                        <Sampel Attribute1='asdf' Attribute2='b' Attribute3='3' Attribute4='name' />
                        <Sampel Attribute1='' Attribute2='' Attribute3='66' Attribute4='attri' />
                        <Sampel Attribute1='' Attribute2='b' Attribute3='' Attribute4='sampelname' />
                        </Sampels>";
        dynamic Sampels = DynamicXml.Parse(samples);
        foreach(var sample1 in Sampels.Sampel)
        {
            Console.WriteLine(sample1.Attribute4);
        }
}
// using http://stackoverflow.com/questions/13704752/deserialize-xml-to-object-using-dynamic
public class DynamicXml : System.Dynamic.DynamicObject
{
    XElement _root;
    private DynamicXml(XElement root)
    {
        _root = root;
    }
    public static DynamicXml Parse(string xmlString)
    {
        return new DynamicXml(XDocument.Parse(xmlString).Root);
    }
    public static DynamicXml Load(string filename)
    {
        return new DynamicXml(XDocument.Load(filename).Root);
    }
    public override bool TryGetMember(System.Dynamic.GetMemberBinder binder, out object result)
    {
        result = null;
        var att = _root.Attribute(binder.Name);
        if (att != null)
        {
            result = att.Value;
            return true;
        }
        var nodes = _root.Elements(binder.Name);
        if (nodes.Count() > 1)
        {
            result = nodes.Select(n => new DynamicXml(n)).ToList();
            return true;
        }
        var node = _root.Element(binder.Name);
        if (node != null)
        {
            if (node.HasElements)
            {
                result = new DynamicXml(node);
            }
            else
            {
                result = node.Value;
            }
            return true;
        }
        return true;
    }
}
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