将订单行聚合为订单摘要-如何获取数量
本文关键字:获取 何获取 单行聚 单摘 | 更新日期: 2023-09-27 18:28:17
我有以下扁平结构:
Name1 | Name2 | Price | SubName | SubPrice
------+-------+-------+---------+---------
A | one | 10 | X | 5
A | one | 10 | Y | 7
A | one | 10 | Z | 11
A | one | 10 | X | 5
A | one | 10 | Y | 7
A | one | 10 | Z | 11
A | two | 16 | X | 5
A | null | 9 | null | null
B | three | 24 | null | null
它需要转换为以下内容:
{
0 = {
Name = "A one X, Y, Z",
Quantity = 2,
TotalPrice = 66,
},
1 = {
Name = "A two X",
Quantity = 1,
TotalPrice = 21,
},
2 = {
Name = "A",
Quantity = 1,
TotalPrice = 9,
},
3 = {
Name = "B three",
Quantity = 1,
TotalPrice = 24,
}
}
理论很简单——.GroupBy()
是Name1和Name2——问题是,一旦我从群中得到.Select()
,我就永远无法得到正确的数量。。。我知道这应该很简单,但我似乎无法理解…
items
.GroupBy(item => new
{
item.Name1,
item.Name2,
})
.Select(grouping => new
{
Name = grouping.Key.Name1 + " " + grouping.Key.Name2,
Price = grouping.Key.Price,
Subs = grouping.GroupBy(groupItem => new
{
groupItem.SubName,
groupItem.SubPrice,
}),
})
.Select(temp => new
{
Name = temp.Name + (temp.Subs.Any() ? " " + temp.Subs.Select(sub => sub.SubName).Aggregate((a, b) => (a + ", " + b)) : string.Empty),
FullItemPrice = temp.Price + temp.Subs.Sum(subPrice => subPrice ?? 0m),
Quantity = ???,
})
.Select(output => new
{
output.Name,
output.Quantity,
TotalPrice = output.FullItemPrice * output.Quantity,
});
var source = new List<Item>(9) {
new Item { Name1 = "A", Name2 = "One", Price = 10, SubName = "X", SubPrice = 5},
new Item { Name1 = "A", Name2 = "One", Price = 10, SubName = "Y", SubPrice = 7},
new Item { Name1 = "A", Name2 = "One", Price = 10, SubName = "Z", SubPrice = 11},
new Item { Name1 = "A", Name2 = "One", Price = 10, SubName = "X", SubPrice = 5},
new Item { Name1 = "A", Name2 = "One", Price = 10, SubName = "Y", SubPrice = 7},
new Item { Name1 = "A", Name2 = "One", Price = 10, SubName = "Z", SubPrice = 11},
new Item { Name1 = "A", Name2 = "Two", Price = 16, SubName = "X", SubPrice = 5},
new Item { Name1 = "A", Name2 = null, Price = 9, SubName = null, SubPrice = 0 },
new Item { Name1 = "B", Name2 = "three", Price = 24, SubName = null, SubPrice = 0}
};
var grouped = source.GroupBy(x => new { x.Name1, x.Name2 })
.Select(g => new
{
Name = string.Format("{0} {1} {2}", g.Key.Name1, g.Key.Name2, string.Join(", ", g.Select(x => x.SubName))).Trim(),
Quantity = g.Count() / g.Select(x => x.SubName).Distinct().Count()
})
.ToList();
但是您仍然需要实现Price
计算逻辑。