Gridview不显示,而我运行我的代码
本文关键字:运行 我的 代码 显示 Gridview | 更新日期: 2023-09-27 17:54:49
我想显示三列字段作为下拉列表和其他文本框格式。我写的代码显示下拉列表值从我的数据库,但它不工作。我已附上我的代码供您参考
<asp:GridView ID="Gv1" runat="server" AutoGenerateColumns="False">
<Columns>
<asp:TemplateField HeaderText="FacultyName">
<ItemTemplate>
<asp:Label ID="lblfaculty" runat="server" Text='<%%# Eval("facultyname") %>>' Visible="false" />
<asp:DropDownList ID="ddlfaculty" runat="server" OnSelectedIndexChanged="ddlfaculty_SelectedIndexChanged"></asp:DropDownList>
</ItemTemplate>
</asp:TemplateField>
<asp:TemplateField HeaderText="Subject">
<ItemTemplate>
<asp:Label ID="lblsubject" runat="server" Text='<%%# Eval("subject") %>>' Visible="false" />
<asp:DropDownList ID="ddlsubject" runat="server" OnSelectedIndexChanged="ddlsubject_SelectedIndexChanged"></asp:DropDownList>
</ItemTemplate>
</asp:TemplateField>
<asp:TemplateField HeaderText="Subject">
<ItemTemplate>
<asp:Label ID="lblsubject" runat="server" Text='<%%# Eval("subject") %>>' Visible="false" />
<asp:DropDownList ID="ddlsubject" runat="server" OnSelectedIndexChanged="ddlsubject_SelectedIndexChanged1"></asp:DropDownList>
</ItemTemplate>
</asp:TemplateField>
<asp:TemplateField>
<ItemTemplate>
<asp:Label ID="lblsubject" runat="server" Text='<%%# Eval("sethour") %>>' Visible="false" />
<asp:TextBox ID="ddlsethour" runat="server"></asp:TextBox>
</ItemTemplate>
</asp:TemplateField>
<asp:TemplateField>
<ItemTemplate>
<asp:Label ID="lblcount" runat="server" Visible="false" />
<asp:TextBox ID="Count" runat="server"></asp:TextBox>
</ItemTemplate>
</asp:TemplateField>
</Columns>
</asp:GridView>
后台代码:public partial class transhonorarium : System.Web.UI.Page
{
protected void Page_Load(object sender, EventArgs e)
{
}
protected void ddlfaculty_SelectedIndexChanged(object sender, EventArgs e)
{
using (SqlConnection con = new SqlConnection(ConfigurationManager.ConnectionStrings["ConnectionString"].ConnectionString))
{
SqlDataAdapter cmd = new SqlDataAdapter("select facultyname from faculty", con);
DataTable dt = new DataTable("dt");
cmd.Fill(dt);
Gv1.DataSource = dt;
Gv1.DataBind();
}
}
protected void ddlsubject_SelectedIndexChanged(object sender, EventArgs e)
{
using (SqlConnection con = new SqlConnection(ConfigurationManager.ConnectionStrings["ConnectionString"].ConnectionString))
{
SqlDataAdapter cmd = new SqlDataAdapter("select subject from assign where facultyname=@facultyname", con);
DataTable dt = new DataTable("dt");
cmd.Fill(dt);
Gv1.DataSource = dt;
Gv1.DataBind();
}
}
}
你需要改变一件事。
-
AutoGenerateColumns = true
。因此,您将能够看到分配的列及其数据。
其次,
您需要在Page_load
或您想要的地方Bind
您的Gridview。这是页面加载。
protected void Page_Load(object sender, EventArgs e)
{
if (!Page.IsPostBack)
{
Gv1.DataSource = Somesource;
Gv1.DataBind();
}
}
参见Bind Data
public void BindData()
{
SqlCommand comd = new SqlCommand("SELECT * FROM Yourtablename", con);
SqlDataAdapter da = new SqlDataAdapter(comd);
DataTable dt = new DataTable();
da.Fill(dt);
GV1.DataSource = dt;
GV1.DataBind();
}
希望有帮助
在数据发生变化时调用Gridview的DataBind()
方法
我会这样做:
protected override void OnPreRender(Eventargs e)
{
base.OnPreRender(e);
GV1.DataBind();
}
为了填充下拉列表,您应该实现_RowDataBound事件,并根据您的选择更新数据集,您还应该为下拉对象实现RowCommand事件。
顺便说一句。在ddlsubject_SelectedIndexChanged中,您还需要向sql命令添加参数以使sql字符串工作,