在 C# 中分析 XML 数据并显示在列表框中

XmlSerializer mySerializer = new XmlSerializer(typeof(Persons));
// Create a FileStream or textreader to read the xml data.
FileStream myFileStream = new FileStream("xmldatafile.xml", FileMode.Open);
var person = (Persons)  mySerializer.Deserialize(myFileStream);

您还需要为 Person 类添加不带参数的构造函数。

最自然的方法是使用 XmlSerializer ，正如建议的那样，但要做到这一点，你必须稍微重构你的类：

[XmlType(Namespace="", TypeName="root")]
public class PersonCollection
{
    [XmlElement(Namespace="", ElementName="Persons")]
    public List<Persons> People { get; set; }
}
public class Persons
{
    [XmlAttribute(AttributeName="name")]
    public string Name { get; set; }
    public int Age { get; set; }
    public bool IsMale { get; set; }
    public Persons LikedPerson { get; set; }
    public Persons() { }
    public Persons(string name, int age, bool isMale, Persons likedPerson)
    {
        Name = name;
        Age = age;
        IsMale = isMale;
        LikedPerson = likedPerson;
    }
}

然后你可以做这样的事情：

XmlSerializer ser = new XmlSerializer(typeof(PersonCollection));
PersonCollection pc = (PersonCollection)ser.Deserialize(File.OpenRead("Baza_de_cunostinte.xml"));
foreach (Persons p in pc.People)
{
   // you now have a fully populated object
}

pc.People列表将包含您的Persons对象。

@user3063909，

1-对XML定义使用XSD。前任：

<xs:schema attributeFormDefault="unqualified" elementFormDefault="qualified" xmlns:xs="http://www.w3.org/2001/XMLSchema">
  <xs:element name="root">
    <xs:complexType>
      <xs:sequence>
        <xs:element name="Persons" maxOccurs="unbounded" minOccurs="0" type="Persons"/>
      </xs:sequence>
    </xs:complexType>
  </xs:element>
  <xs:complexType name="Persons">
    <xs:sequence>
      <xs:element type="xs:string" name="IsMale"/>
      <xs:element type="xs:int" name="Age"/>
      <xs:element name="LikedPerson" type="Persons"/>
    </xs:sequence>
    <xs:attribute type="xs:string" name="name" />
  </xs:complexType>
</xs:schema>   

2-人员类应如下所示：

namespace StackOverflow
{
    public class Root
    {
        [XmlElement("Persons")]
        public List<Persons> Persons { get; set; }
    }
    public class Persons
    {
        public string IsMale { get; set; }
        public int Age { get; set; }
        public Persons LikedPerson { get; set; }
        [XmlAttribute("Name")]
        public string Name { get; set; }
    }
}

3-序列化程序类：

namespace StackOverflow
{
    public class XmlSerializerHelper<T> where T : class 
    {
        private readonly XmlSerializer _serializer;
        public XmlSerializerHelper()
        {
            _serializer = new XmlSerializer(typeof(T));
        }
        public T BytesToObject(byte[] bytes)
        {
            using (var memoryStream = new MemoryStream(bytes))
            {
                using (var reader = new XmlTextReader(memoryStream))
                {
                    return (T)_serializer.Deserialize(reader);
                }
            }
        }
    }
}

4-最后，这样称呼它：

var fileBytes = File.ReadAllBytes("C:/xml.xml");
var persons = new XmlSerializerHelper<Root>().BytesToObject(fileBytes);

结果，将是带有人员列表的根类。

干杯。

你可以像现在一样获取 LikedPerson 节点并获取它的名称/年龄。为了避免代码重复，您可以创建一个方法，该方法采用 XmlNode，递归分析它并返回 Person。但更好的方法是使用 XmlSerializer

foreach (XmlNode node in doc.DocumentElement) 
{
    string name = node.Attributes[0].Value;
    int age = int.Parse(node["Age"].InnerText);
    bool isMale = bool.Parse(node["IsMale"].InnerText);
    var likedPerson = node.SelectSingleNode("LikedPerson");
    if (likedPerson != null){
        string name = likedPerson.Attributes[0].Value;
        //age, gender, etc.        
    }        
}