C# 如何将附件保存到文件夹? .净2.

本文关键字：文件夹 保存 | 更新日期: 2023-09-27 18:32:39

我正在创建一个csv文件并将其附加到像这样的电子邮件中...

using (MemoryStream stream = new MemoryStream(Encoding.ASCII.GetBytes(csv)))
            {
                try
                {
                    to = "email@email.com";
                    string from = "user@email.co.uk";
                    string subject = "Order p"+ OrderNumber;
                    string body = result;
                    SmtpClient SMTPServer = new SmtpClient("127.0.0.1");
                    MailMessage mailObj = new MailMessage(from, to, subject, body);
                    Attachment attachment = new Attachment(stream, new ContentType("text/csv"));
                    attachment.Name = "p" + OrderNo + "_" + CustomerReference+".csv";
                    mailObj.Attachments.Add(attachment);
                    SMTPServer.Send(mailObj);
                }
                catch (Exception ex)
                { }
            }

这工作正常，但是如何将相同的csv文件保存到文件夹中？谢谢

C# 如何将附件保存到文件夹? .净2.

System.IO 中的File.WriteAllText方法可能是实现此目的的最简单方法：

File.WriteAllText("<destination>", csv);

其中<destination>是要将 CSV 保存到的文件的路径。如果此文件尚不存在，则将创建该文件，否则将被覆盖。

您必须将流保存到某个位置：

var newfile = new StreamWriter(path_filename);
foreach (var l in stream)
   newfile.WriteLine(l);
newfile.Close();

编辑：

请改用这个：

StreamWriter outputfile = new StreamWriter("c:'temp'outputfile.csv");

然后是 foreach 循环。

已编辑 2（来自 msdn 站点）：

   // Read the first 20 bytes from the stream.
   byteArray = new byte[memStream.Length];
   count = memStream.Read(byteArray, 0, 20);
   // Read the remaining bytes, byte by byte.
   while(count < memStream.Length)
            {
                byteArray[count++] = 
                    Convert.ToByte(memStream.ReadByte());
            }
   // Decode the byte array into a char array 
   // and write it to the console.
   charArray = new char[uniEncoding.GetCharCount(
   byteArray, 0, count)];
   uniEncoding.GetDecoder().GetChars(
                byteArray, 0, count, charArray, 0);
            Console.WriteLine(charArray); //here you should send to the file as the first example i wrote instead of to writing to console.
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