使用 C# 将树视图转换为 JSON
本文关键字：转换 JSON 视图 使用 | 更新日期: 2023-09-27 18:33:54
我必须使用 C# 将TreeView对象转换为 JSON。我目前正在使用JsonConvert.SerializeObject().
public class SubTreeNode : TreeNode
{
public CustomProperties customProperties;
}
public class CustomProperties
{
public string property1 = "Property1";
public string property2 = "Property2";
public string property3 = "Property3";
}
当尝试使用它时JsonConvert.SerializeObject(treeView1.Nodes);它只返回顶部节点......不是子节点、子节点等。
序列化和反序列化此 TreeView 对象的最简单方法是什么？
您需要添加以递归方式从每个节点生成 JSON 的方法。
查看相关文章：将树序列化为 json 对象。
我遇到了同样的问题：只有顶级节点使用标准 JSON.Net 序列化程序导出，因为正如上述链接下的fero正确指出的那样，"您的TreeNode类被序列化为数组，因为它实现了IEnumerable"。它进一步说你应该用JsonConverterAttribute装饰TreeNode类。我没有让这个工作。
这是一个替代方案。请注意，这可能不被视为最佳方法。但这很简单：
- 您使用的是标准 TreeNode 类，并且您的数据存储在 TreeView 中
- 您想使用 JSON.NET 序列化程序
使用要在 JSON 中导出的信息创建一个新的分层类(就我而言，我只想导出我的部分 treenode-属性，因此创建一个新的简单类两次有意义(：
'Simplified version of tree for json
'Compared to TreeNode class, this object is also serializable with the standard JSON.NET Serializer
Public Class JTree
Public children As New List(Of JTree)()
Private _name As String
Public Property name() As String
Get
Return _name
End Get
Set(value As String)
_name = value
End Set
End Property
Private _id As String
Public Property id() As String
Get
Return _id
End Get
Set(value As String)
_id = value
End Set
End Property
End Class
归地将数据从 TreeView 移动到新的 JTree(我们的自定义类(：
Public Sub createSimplifiedJSONTree(parentNode As TreeNode, ByRef JTreeSimp As JTree)
'Start recursion on all subnodes
For Each childNode As TreeNode In parentNode.Nodes
Dim jchild As New JTree
jchild.id = childNode.Name
jchild.name = childNode.Text
JTreeSimp.children.Add(jchild)
createSimplifiedJSONTree(childNode, jchild)
Next
End Sub
使用序列化程序将简化的 JSON 树写入文件 JSON.NET：
Private Sub WriteJSONfromTreeview()
Dim rootNode As TreeNode = TreeView1.Nodes(0)
Dim JTreeSimp As New JTree
createSimplifiedJSONTree(rootNode, JTreeSimp)
'serialize JSON directly to a file using JSON.Net Serializer
Using file__1 As StreamWriter = File.CreateText("c:'temp'test.txt")
Dim serializer As New JsonSerializer()
serializer.Formatting = Formatting.Indented
serializer.Serialize(file__1, JTreeSimp)
End Using
End Sub
最终 txt(示例(：
{
"children": [
{
"children": [
{
"children": [
{
"children": [
{
"children": [
{
"children": [
{
"children": [
{
"children": [],
"name": "alcatraz",
"id": "021_3",
"size": 166
}
],
"name": "skyline",
"id": "031_3",
"size": 167
}
],
"name": "city",
"id": "041_5",
"size": 167
}
],
"name": "coit",
"id": "051_4",
"size": 169
}
],
"name": "tower",
"id": "061_3",
"size": 170
}
],
"name": "telegraphhill",
"id": "071_3",
"size": 170
}
],
"name": "coittower",
"id": "081_2",
"size": 170
},
{
"children": [
{
"children": [],
"name": "sunset",
"id": "071_112",
"size": 3
}
],
"name": "berkeley",
"id": "081_109",
"size": 3
},
{
"children": [
{
"children": [],
"name": "marin",
"id": "071_77",
"size": 3
}
],
"name": "marinheadlands",
"id": "081_110",
"size": 3
}
],
"name": "root",
"id": "000",
"size": 0
}
这是我
的解决方案：
- 首先，我创建一个节点类，其中包含
我想要的节点数据结构，以及一个序列化对象的 JSon 方法
[JsonObject(ItemNullValueHandling = NullValueHandling.Ignore)] private class node { public node() { this.children = new List<node>(); } public node(string _value, List<node> _children = null, bool _isChecked = false) { Value = _value; isChecked = _isChecked; if (_children != null) { children = _children; } } [JsonProperty("value")] public string Value { get; set; } [JsonProperty("isChecked")] public bool isChecked { get; set; } [JsonProperty("children", NullValueHandling = NullValueHandling.Ignore)] public List<node> children { get; set; } [JsonIgnore] public string JSon { get { return JsonConvert.SerializeObject(this); } } }
我写了一个方法，它应该递归调用。这将返回给定特定树节点的子节点列表
private List<node> RunNode(TreeNode node) { List<node> nodeOut = new List<node>(); foreach(TreeNode child in node.Nodes) { List<node> grandchild = RunNode(child); nodeOut.Add(new node(child.Text, grandchild, child.Checked)); } return nodeOut; }
我编写并更新了对象方法来创建一个根节点，我可以在其中包含树视图的所有节点。我决定使用根节点而不是节点列表，因为列表没有序列化对象的 JSon 方法。
private void ActualizarMenus() { List<node> parents= new List<node>(); foreach (TreeNode node in trw.Nodes) { List<node> childs = RunNode(node); parents.Add(new node(node.Text,childs,node.Checked)); } root = new node("root", parents, true); }根对象必须声明为单个节点
private node root;你可以调用根的JSon方法
MessageBox.show(root.JSon());
我希望这有帮助
使用自定义 JSON 序列化程序对我有用
var settings = new JsonSerializerSettings
{
Converters = new List<JsonConverter> { new OrgChartConverter() },
Formatting = Formatting.Indented
};
string json = JsonConvert.SerializeObject(tree, settings);
public class OrgChartConverter : JsonConverter
{
public override bool CanConvert(Type objectType)
{
return typeof(Node<T>).IsAssignableFrom(objectType);
}
public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
{
Node<T> node = (Node<T>)value;
JObject obj = new JObject();
obj.Add("Name", node.Value.Name);
obj.Add("Children", JArray.FromObject(node.Children, serializer));
obj.WriteTo(writer);
}
public override bool CanRead
{
get { return false; }
}
public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
{
throw new NotImplementedException();
}
}