动态地将元素添加到 XML 文件
本文关键字：XML 文件 添加 元素 动态 | 更新日期: 2023-09-27 18:34:18
我目前正在使用此代码创建一个XML文件，其中我创建了一个对象，每次调用该方法时都会将其写入XML文件：
public static void TileMapCapabilities(string title, TilePicker picker)
{
var dbInfo = picker.GetCapabilitiesInfo();
TileMapObject tmo = new TileMapObject()
{
Title = title,
Abstract = "",
KeywordList = new KeywordList() {FirstLayer = ""},
SRS = "OSGEO:41001",
Profile = "local",
Format = "image/png",
BoundingBox = dbInfo.eBoundingBox,
MapSize = dbInfo.mapSize,
CellSize = dbInfo.cellSize,
MaxLevel = dbInfo.level,
Location = dbInfo.location // Not sure if this should be here. Could be practical in scenarios where the tile server is hosted locally.
};}
它工作正常，可能如下所示：
<?xml version="1.0" encoding="utf-8"?>
<TileMapServicesObject xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<TileMapService>
<Title>EivaTMS</Title>
<Abstract>Something clever about this service</Abstract>
<TileMaps>
<TileMap>
<Title>kraken.db</Title>
<href>10.10.100.200/kraken.db?request=getcapabilities</href>
<Profile>global-mercator</Profile>
<SRS>OSGEO:41001</SRS>
</TileMap>
</TileMaps>
</TileMapService>
</TileMapServicesObject>
现在，我想做的是创建一个XML文件，该文件描述了上面提到的层。换句话说，我想要一个XML文件，其中包含上面每个XML文件的简短描述。
我已经设法做了一些工作，如果我对值进行硬编码，它将如下所示：
public static void TileMapServicesCapabilities(int listBoxCount)
{
TileMapServicesObject tmso = new TileMapServicesObject()
{
TileMapService = new TileMapService()
{
Title = "EivaTMS",
Abstract = "Something clever about this service",
TileMaps = new List<TileMap>
{
new TileMap { Title = "title1", href = "http://title1/?request=getcapabilities", Profile = "global-mercator", SRS = "OSGEO:41001"},
new TileMap { Title = "title2", href = "http://title2/?request=getcapabilities", Profile = "global-mercator", SRS = "OSGEO:41001"},
new TileMap { Title = "title3", href = "http://title3/?request=getcapabilities", Profile = "global-mercator", SRS = "OSGEO:41001"}
}
}
};}
产生此输出：
<?xml version="1.0" encoding="utf-8"?>
<TileMapServicesObject xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<TileMapService>
<Title>EivaTMS</Title>
<Abstract>Something clever about this service</Abstract>
<TileMaps>
<TileMap>
<Title>title1</Title>
<href>http://title1/?request=getcapabilities</href>
<Profile>global-mercator</Profile>
<SRS>OSGEO:41001</SRS>
</TileMap>
<TileMap>
<Title>title2</Title>
<href>http://title2/?request=getcapabilities</href>
<Profile>global-mercator</Profile>
<SRS>OSGEO:41001</SRS>
</TileMap>
<TileMap>
<Title>title3</Title>
<href>http://title3/?request=getcapabilities</href>
<Profile>global-mercator</Profile>
<SRS>OSGEO:41001</SRS>
</TileMap>
</TileMaps>
</TileMapService>
</TileMapServicesObject>
现在，我想做的是动态创建和添加元素。这意味着对于我通过第一个方法创建的每个XML文件TileMapCapabilities，我想创建一个对象并将其添加到TileMapServicesObject中。可能还值得一提的是包含正在创建的对象中信息的类的外观：
public class TileMapServicesObject
{
public TileMapService TileMapService { get; set; }
}
public class TileMapService
{
public string Title { get; set; }
public string Abstract { get; set; }
public List<TileMap> TileMaps { get; set; }
}
public class TileMap
{
public string Title { get; set; }
public string href { get; set; }
public string Profile { get; set; }
public string SRS { get; set; }
}
我一直在尝试使用 foreach 循环为我添加到服务中的每个 TileMap 创建一个 TileMap 对象，但这只是为每个迭代创建了一个新的 TileMapServicesObject，而不是包含所有对象的单个文件。
关于我如何解决这个问题的任何提示？如果我的请求在当前形式上太模糊，请告诉我。
编辑：原来只是盯着它足够长的时间修复它！
以下是更新的代码：
public static void TileMapServicesCapabilities()
{
TileMapServicesObject tmso = new TileMapServicesObject();
List<string> pathList = new List<string>();
pathList = Directory.GetFiles(path + @"Tilemaps'").ToList();
List<TileMap> tmList = new List<TileMap>();
TileMap tm = new TileMap();
string title = "";
string profile = "";
string srs = "";
foreach (var p in pathList)
{
var xRead = XDocument.Load(p);
var xd = (from el in xRead.Descendants("TileMapObject")
select new
{
Title = el.Element("Title").Value,
Profile = el.Element("Profile").Value,
SRS = el.Element("SRS").Value
}).SingleOrDefault();
title = xd.Title;
profile = xd.Profile;
srs = xd.SRS;
tm = new TileMap()
{
Title = title,
Profile = profile,
SRS = srs,
href = "http://10.10.100.200/" + title + "?request=getcapabilities"
};
tmList.Add(tm);
}
tmso = new TileMapServicesObject()
{
TileMapService = new TileMapService()
{
Title = "EivaTMS",
Abstract = "Something clever about this service",
TileMaps = tmList
}
};
这给了我这个漂亮的XML文件：
<?xml version="1.0" encoding="utf-8"?>
<TileMapServicesObject xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<TileMapService>
<Title>EivaTMS</Title>
<Abstract>Something clever about this service</Abstract>
<TileMaps>
<TileMap>
<Title>title1</Title>
<href>http://title1?request=getcapabilities</href>
<Profile>local</Profile>
<SRS>OSGEO:41001</SRS>
</TileMap>
<TileMap>
<Title>title2</Title>
<href>http://title2?request=getcapabilities</href>
<Profile>local</Profile>
<SRS>OSGEO:41001</SRS>
</TileMap>
<TileMap>
<Title>title3</Title>
<href>http://title3?request=getcapabilities</href>
<Profile>local</Profile>
<SRS>OSGEO:41001</SRS>
</TileMap>
<TileMap>
<Title>title4</Title>
<href>http://title4?request=getcapabilities</href>
<Profile>local</Profile>
<SRS>OSGEO:41001</SRS>
</TileMap>
</TileMaps>
</TileMapService>
</TileMapServicesObject>
好吧，经过几个小时的盯着它，我设法修复了这个问题！
事实证明，我可以创建一个foreach((，在其中迭代要从中读取的所有文件，创建一个TileMap对象并将其添加到列表中，然后在foreach((之后将其写入XML。我已经用我的新代码更新了 OP。