unity游戏引擎-在C#中格式化大数字
本文关键字：格式化 数字 游戏 引擎 unity | 更新日期: 2023-09-27 17:59:08
我正在使用Unity制作一个"增量游戏"，也称为"空闲游戏"，我正在尝试格式化大数字。例如，当gold达到1000或更多时，它将显示为Gold: 1k而不是Gold: 1000。
using UnityEngine;
using System.Collections;
public class Click : MonoBehaviour {
public UnityEngine.UI.Text GoldDisplay;
public UnityEngine.UI.Text GPC;
public double gold = 0.0;
public int gpc = 1;
void Update(){
GoldDisplay.text = "Gold: " + gold.ToString ("#,#");
//Following is attempt at changing 10,000,000 to 10.0M
if (gold >= 10000000) {
GoldDisplay.text = "Gold: " + gold.ToString ("#,#M");
}
GPC.text = "GPC: " + gpc;
}
public void Clicked(){
gold += gpc;
}
}
我在网上搜索时尝试过其他例子，这就是gold.ToString ("#,#");的来源，但都不起作用。
轻微重构：
public static string KMBMaker( double num )
{
double numStr;
string suffix;
if( num < 1000d )
{
numStr = num;
suffix = "";
}
else if( num < 1000000d )
{
numStr = num/1000d;
suffix = "K";
}
else if( num < 1000000000d )
{
numStr = num/1000000d;
suffix = "M";
}
else
{
numStr = num/1000000000d;
suffix = "B";
}
return numStr.ToString() + suffix;
}
用途：
GoldDisplay.text = KMBMaker(gold);
更改：
- 显式使用
double常量 - 删除重复
- 单独的关注点-此方法无需了解文本框
我不认为有内置的方法，所以我可能只是通过自己的方式重新发明了轮子，但这应该是我可能会做的
using System;
using System.Collections.Generic;
namespace ConsoleApplication1
{
class Program
{
static void Main(string[] args)
{
for (double i = 500d; i < 5e23; i *= 100d)
{
Console.WriteLine(i.ToMyNumber());
}
Console.Read();
}
}
public static class helper
{
private static readonly List<string> myNum;
static helper()
{
myNum = new List<string>();
myNum.Add("");
myNum.Add("kilo");
myNum.Add("mill");
myNum.Add("bill");
myNum.Add("tril");
myNum.Add("quad");
myNum.Add("quin");
myNum.Add("sext");
// ....
}
public static string ToMyNumber(this double value)
{
string initValue = value.ToString();
int num = 0;
while (value >= 1000d)
{
num++;
value /= 1000d;
}
return string.Format("{0} {1} ({2})", value, myNum[num], initValue);
}
}
}
谁打印这个
500 (500)
50 kilo (50000)
5 mill (5000000)
500 mill (500000000)
50 bill (50000000000)
5 tril (5000000000000)
500 tril (500000000000000)
50 quad (5E+16)
5 quin (5E+18)
500 quin (5E+20)
50 sext (5E+22)
我在我的项目中使用这个方法，你也可以使用。也许还有更好的办法，我不知道。
public void KMBMaker( Text txt, double num )
{
if( num < 1000 )
{
double numStr = num;
txt.text = numStr.ToString() + "";
}
else if( num < 1000000 )
{
double numStr = num/1000;
txt.text = numStr.ToString() + "K";
}
else if( num < 1000000000 )
{
double numStr = num/1000000;
txt.text = numStr.ToString() + "M";
}
else
{
double numStr = num/1000000000;
txt.text = numStr.ToString() + "B";
}
}
并像这样在更新中使用此方法。
void Update()
{
KMBMaker( GoldDisplay.text, gold );
}
我使用这个：
private static List<string> nFormat= new List<string>();
void Awake()
{
nFormat.Add("");
nFormat.Add("K");
nFormat.Add("M");
nFormat.Add("B");
//...
}
public static string Double2dec(double value)
{
int num = 0;
while (value >= 1000d)
{
num++;
value /= 1000d;
}
return value.ToString("F2") + nFormat[num];
}
我尝试了这里给出的一些解决方案，但由于需要记下从K到NoNod的所有缩写，我被推迟了，所以我写了这篇文章——尽管我还没有尝试它是否会对性能产生很大影响（尽管它似乎像使用科学符号一样流畅）。
using System;
//System.Numerics necessary for us of BigInteger only - alternatively use double (which might be faster, but more inaccurate
using System.Numerics;
namespace WPF_Clicker
{
public static class NumberFormatter
{
/*NumberFormat
* Scientific => 0.0e0 | example: 1.234e14 -> 123,400,000,000,000
* Abbreviation => 0.0xx | example: 123.4T -> 123,400,000,000,000
*/
public enum NumberFormat
{
Scientific,
Abbreviation
}
public static string FormatNumber(BigInteger number, NumberFormat format = NumberFormat.Scientific)
{
if (format == NumberFormat.Scientific)
return ScientificFomat(number);
else
return AbbreviationFormat(number);
}
public static string ScientificFomat(BigInteger number)
{
if (number < 1000)
//if number smaller than 1,000, don't use special format
return number.ToString("#.##0");
else
//return number as scientific notation with 1 place before and 3 places after decimal point
return number.ToString("e3");
}
public static string AbbreviationFormat(BigInteger number)
{
if (number < 1000)
//if number smaller than 1,000, don't use special format
return number.ToString("#.##0");
//get division of number (string length - 1) by 3 and get remainder -> appendix changes with every 4 characters
int decider = Math.DivRem(number.ToString().Length - 1, 3, out int remainder) - 1;
//if decider is bigger than 9, looping for every place of the decider number
int declength = decider.ToString().Length;
//string is necessary to decide on which appendix to use
string decstring = decider.ToString();
//string for the appendix
string appendix = "";
if (decider > 99)
//return "infinity" if decider is greater than 99
//can be changed if you decide to go over NoNod (decider > 99)
return "infinity";
else
{
//thousands, millions and billions are special cases
if (decider < 3)
{
if (decider == 0)
appendix = "K";
else if (decider == 1)
appendix = "M";
else if (decider == 2)
appendix = "B";
else
appendix = "";
}
else
//loop through for decider number string
//start at the last place, since these will be definite and it saves the check of whether there is more than 1 place in the decider number string
for (int counter = declength - 1; counter >= 0; counter--)
{
char decchar = decstring[counter];
//handle last place of decider number string
if (counter == declength - 1)
if (decchar == '1')
appendix = "U";
else if (decchar == '2')
appendix = "D";
else if (decchar == '3')
appendix = "T";
else if (decchar == '4')
appendix = "Qa";
else if (decchar == '5')
appendix = "Qi";
else if (decchar == '6')
appendix = "Sx";
else if (decchar == '7')
appendix = "Sp";
else if (decchar == '8')
appendix = "Oc";
else if (decchar == '9')
appendix = "No";
else
appendix = "";
else
//handles second place (or higher) of decider number string
{
if (decchar == '1')
appendix += "Dc";
else if (decchar == '2')
appendix += "Vg";
else if (decchar == '3')
appendix += "Td";
else if (decchar == '4')
appendix += "Qad";
else if (decchar == '5')
appendix += "Qid";
else if (decchar == '6')
appendix += "Sxd";
else if (decchar == '7')
appendix += "Spd";
else if (decchar == '8')
appendix += "Ocd";
else if (decchar == '9')
appendix += "Nod";
}
}
//since the number string is at this point definitly more than 3 places long, use the remainder to set the decimal point
string numberstr = number.ToString().Substring(0, 4).Insert(remainder + 1, ",");
//put the number with decimal point together with the appendix | example: 123,456,789,012,345,678,901,234,567,890,123,456,789,012 -> 123,4DDc
return numberstr + appendix;
}
}
}
}
希望这能有所帮助。