如何从运行时可以使用的资源文件中创建和调用类对象

using System;
using System.Reflection;
using System.Resources;
namespace ResourceDemo
{
  internal class Program
  {
    private static void Main(string[] args)
    {
      bool generateMode = false;
      if (generateMode) {
        // After running once with generate mode set to true, add the resulting
        // "StatusItem.resource" that was created in the .'bin'x86'Debug folder
        // to the project.
        Generate();
      }
      else {
        // When run the next line generates an exception:
        //   An unhandled exception of type 'System.Resources.MissingManifestResourceException' occurred in mscorlib.dll
        //
        //   Additional information: Could not find any resources appropriate for the specified culture
        //   or the neutral culture.  Make sure "StatusItems.resources" was correctly embedded or linked
        //   into assembly "ResourceDemo" at compile time, or that all the satellite assemblies required
        //   are loadable and fully signed.
        StatusItem statusItem = GetResource("2");
        Console.WriteLine("Id: {0}  Message: {1}", statusItem.Id.ToString(), statusItem.Message);
        Console.ReadKey();
      }
    }
    public static void Generate()
    {
      StatusItem[] statusItem = new StatusItem[4];
      // Instantiate an Status object items.
      statusItem[0] = new StatusItem(2, "File not found");
      statusItem[1] = new StatusItem(3, "Path not found");
      statusItem[2] = new StatusItem(4, "Too many open files");
      statusItem[3] = new StatusItem(5, "File access denied");
      // Define a resource file named StatusItems.resx.
      using (System.Resources.ResourceWriter rw = new ResourceWriter(@".'StatusItems.resources")) {
        for (int i = 0; i < 4; i++) {
          rw.AddResource(statusItem[i].Id.ToString(), statusItem[i]);
        }
        rw.Generate();
      }
    }
    public static StatusItem GetResource(string key)
    {
      Assembly assembly = System.Reflection.Assembly.GetExecutingAssembly();
      System.Resources.ResourceManager rm = new System.Resources.ResourceManager("StatusItems", Assembly.Load("ResourceDemo"));
      return (StatusItem)rm.GetObject(key);
    }
    [Serializable()]
    public class StatusItem
    {
      public StatusItem(int id, string message)
      {
        Id = id;
        Message = message;
      }
      public int Id { get; set; }
      public string Message { get; set; }
    }
  }
}

…并将该文件添加到项目中

如何？您正在IDE中添加文件吗？如果是这样，那就行不通了。。。将文件视为纯二进制数据；它本身并没有被解释为资源数据。您需要在命令行中使用/resource，或者使用al.exe在事实之后嵌入.resource文件。

如果您希望能够简单地将生成的资源输出添加到项目中，那么您可能希望使用ResXResourceWriter而不是ResourceWriter。然后，您将获得一个.resx文件，可以将其直接添加到项目中。Visual Studio将.resx文件编译为.resources文件，并自动正确嵌入。

这还具有生成人类可读文件的优点，并且该文件也可以在IDE中打开（尽管功能有限，具体取决于您放入的类型）。

注意事项：

• ResXResourceWriter类实际上是在System.Windows.Forms.dll中定义的，因此您需要在项目中包含对该程序集的引用
• 写入.resx文件的类型需要能够在编译时被引用，这意味着它们不能在编译的同一程序集中。您需要将它们放在程序引用的单独DLL中
• .resx文件的ResourceManager名称将在您的项目上下文中完全限定。因此，例如，假设将.resx文件添加为项目中的顶级文件，则需要加载"ResourceDemo.StatusItems"，而不仅仅是"StatusItems"。如果添加.resx文件"作为链接"，默认情况下，它将出现在项目中，包含在与文件系统对应的文件夹中，例如"bin''Debug''StatusItems.resx"。在这种情况下，管理器名称将为"ResourceDemo.bin.Debug.StatusItems"

关于最后一点，如果您对名称有任何疑问，可以使用Assembly.GetManifestResourceNames()检查已编译到程序中的名称。

以下代码使用ResourceWriter成功创建了一个非嵌入式资源，并能够使用字典调用数据对象。

它在IDE中似乎运行良好。我试图在命令行编译它，但遇到了一些其他问题，最好留给单独的问题处理。我认为这更多地与命令行编译有关，而不是与代码有关。

我想发布一些具体回答这个问题的内容，尽管我可能会采纳Peter Duniho的建议，转而使用ResxResourceWriter家族。

using System;
using System.Collections;
using System.Collections.Generic;
using System.Resources;
namespace ResourceDemo
{
  internal class Program
  {
    private const string nameSpace = "ResourceDemo";
    private const string resourceExtension = ".resources";
    private const string resourceFilename = "StatusItems";
    private static IDictionary<string, StatusItem> dictionary;
    private static void Main(string[] args)
    {
      bool generateMode = false;
      if (generateMode) {
        // Only run when a new resource is added
        Generate();
      }
      else {
        // Show the contents of the resource
        EnumerateResource();
        // Make a dictionary so it is usable
        BuildDictionary();
        Console.WriteLine("Look-up items 2, 4, 42 and 3 in dictionary");
        WriteStatusItemToConsole(GetResource("2"));
        WriteStatusItemToConsole(GetResource("4"));
        WriteStatusItemToConsole(GetResource("42"));
        WriteStatusItemToConsole(GetResource("3"));
        Console.ReadKey();
      }
    }
    /// <summary>
    /// Build the working dictionary from the resource file
    /// </summary>
    public static void BuildDictionary()
    {
      Console.WriteLine("Building a look-up dictionary");
      StatusItem statusItem;
      dictionary = new Dictionary<string, StatusItem>();
      ResourceReader res = new ResourceReader(@".'" + resourceFilename + resourceExtension);
      IDictionaryEnumerator dict = res.GetEnumerator();
      while (dict.MoveNext()) {
        statusItem = (StatusItem)dict.Value;
        dictionary.Add(dict.Key.ToString(), statusItem);
      }
      res.Close();
      Console.WriteLine("{0} items written to dictionary.", dictionary.Count.ToString());
      Console.WriteLine();
    }
    /// <summary>
    /// List all the items inside the resource file. Assuming that the
    /// </summary>
    public static void EnumerateResource()
    {
      StatusItem statusItem;
      Console.WriteLine("Resources in {0}", resourceFilename + resourceExtension);
      ResourceReader res = new ResourceReader(@".'" + resourceFilename + resourceExtension);
      IDictionaryEnumerator dict = res.GetEnumerator();
      Console.WriteLine("Dictionary Enumeration ready");
      while (dict.MoveNext()) {
        statusItem = (StatusItem)dict.Value;
        Console.WriteLine("   {0}: '{1}, {2}' (Type: {3})", dict.Key, statusItem.Id.ToString(), statusItem.Message, dict.Value.GetType().Name);
      }
      res.Close();
      Console.WriteLine();
    }
    /// <summary>
    /// Called to create the binary resource file. Needs to be called once.
    /// </summary>
    public static void Generate()
    {
      StatusItem[] statusItem = new StatusItem[4];
      // Instantiate some StatusItem objects.
      statusItem[0] = new StatusItem(2, "File not found");
      statusItem[1] = new StatusItem(3, "Path not found");
      statusItem[2] = new StatusItem(4, "Too many open files");
      statusItem[3] = new StatusItem(5, "File access denied");
      // Define a resource file named StatusItems.resx.
      using (System.Resources.ResourceWriter rw = new ResourceWriter(@".'" + resourceFilename + resourceExtension)) {
        for (int i = 0; i < 4; i++) {
          rw.AddResource(statusItem[i].Id.ToString(), statusItem[i]);
        }
        rw.Generate();
      }
    }
    /// <summary>
    /// Look up StatusItem in dictionary with the given key
    /// </summary>
    /// <param name="key"></param>
    /// <returns></returns>
    public static StatusItem GetResource(string key)
    {
      StatusItem result = null;
      if (dictionary != null) {
        dictionary.TryGetValue(key, out result);
      }
      return result;
    }
    /// <summary>
    /// Write the value of the given item to the console
    /// </summary>
    /// <param name="statusItem"></param>
    public static void WriteStatusItemToConsole(StatusItem statusItem)
    {
      if (statusItem != null) {
        Console.WriteLine("   Id: {0}  Message: {1}", statusItem.Id, statusItem.Message);
      }
      else {
        Console.WriteLine("Null Item");
      }
    }
    /// <summary>
    /// This is our sample class
    /// </summary>
    [Serializable()]
    public class StatusItem
    {
      public StatusItem(int id, string message)
      {
        Id = id;
        Message = message;
      }
      public int Id { get; set; }
      public string Message { get; set; }
    }
  }
}