CA2000和返回的Socket对象:如何解决

本文关键字：何解决 解决 返回 Socket 对象 CA2000 | 更新日期: 2023-09-27 17:59:31

我有下一个功能：

    public static Socket ConnectSocket(string srvName, int srvPort)
    {
        Socket tempSocket = null;
        IPHostEntry hostEntry = null;
        try
        {
            hostEntry = Dns.GetHostEntry(srvName);
            //// Loop through the AddressList to obtain the supported AddressFamily. This is to avoid
            //// an exception that occurs when the host IP Address is not compatible with the address family
            //// (typical in the IPv6 case).
            foreach (IPAddress address in hostEntry.AddressList)
            {
                IPEndPoint ipe = new IPEndPoint(address, srvPort);
                if (!ipe.AddressFamily.Equals(AddressFamily.InterNetwork))
                    continue;
                tempSocket = new Socket(ipe.AddressFamily, SocketType.Stream, ProtocolType.Tcp);
                tempSocket.Connect(ipe);
                if (tempSocket.Connected)
                {
                    return tempSocket;
                }
                tempSocket.Close();
            }
            throw new ConnectionThruAddressFamilyFailedException();
        }
finally
{
  //I can't close socket here because I want to use it next
}
    }

在这里的代码分析过程中，我显然有CA2000（在失去作用域之前处理对象）警告。返回的套接字接下来用于和服务器通信。所以我不能在这里处理它。即使我稍后在这里处理这个对象，我也有CA2000。

如何解决这个问题？

CA2000和返回的Socket对象:如何解决

如果有东西抛出异常，您既不返回套接字也不返回Close/Dispose it。

尝试：

try
{
    tempSocket = new Socket(ipe.AddressFamily, SocketType.Stream,
                            ProtocolType.Tcp);
    tempSocket.Connect(ipe);
    if (tempSocket.Connected)
    {
        return tempSocket;
    }
    tempSocket.Close();
    tempSocket = null;
}
catch (Exception)
{
    if (tempSocket != null)
        tempSocket.Close();
    throw;
}
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