如何使用visual c#和streamwriter在循环中更改文本文件的名称

本文关键字：文本 文件 循环 visual 何使用 streamwriter | 更新日期: 2023-09-27 17:59:40

我正试图编写一个循环，读取一个列表，并根据数据采集的时间将该列表的部分保存到不同的文本文件中。我想根据获取数据的小时来命名文本文件。

以下是相关代码：

private StreamWriter filename;
string[] hour = {"00","01","02","03","04","05","06","07","08","09","10","11","12","13","14","15","16","17","18","19","20","21","22","23}
private void btn_hourfiles_click(object sender, EventArgs e)
{
    int sizeoflist = Data_List.Count(); //This is the list containing the data
    for (int i = 0; i<sizeoflist,i++)
    {
       string[] listsplit = Data_List[i].Split(":");
       for (int j = 0; j<24; j++)
       {
           if (listsplit[2] == hour[j])
           {
            string[] datesplit = txt_DATE.Text.Split('-');//splits input date
            filename = datesplit[0] + '_' + dateplit[1] + '_' + datesplit[2] + '_' + hour[j] + '.dat'
            filename = new StreamWriter(new FileStream(Data_List[i], FileMode.Append, FileAccess.Write));
            }
       }
    }
 }

问题：我无法更改StreamWriter filename。我收到一个错误，上面写着：Cannot implicitly convert type string to System.IO.StreamWriter

问题：如何更改变量文件名？

如何使用visual c#和streamwriter在循环中更改文本文件的名称

您发布的代码没有得到编译。下次尝试发布输入，这样帮助和回答您的问题会更简单。不管怎样，我试着根据你上面写的来帮助你，希望它能帮助你

班级计划｛

    static void Main(string[] args)
    {
        MyTest test = new MyTest();
        test.Foo();
    }
}
class MyTest
{
    private StreamWriter streamWriter;
    string[] hour = { "00", "01", "02", "03", "04", "05", "06", "07", "08", "09", "10", "11", "12", "13", "14", "15", "16", "17", "18", "19", "20", "21", "22", "23" };
    public void Foo()
    {
        string txt_DATE = "25-02-2015";
        string[] Data_List = { "12:05:10", "02:15:00", "14:15:22" };
        int sizeoflist = 3; // Data_List.Count(); //This is the list containing the data
        for (int i = 0; i < sizeoflist; i++)
        {
            string[] listsplit = Data_List[i].Split(':');
            for (int j = 0; j < 24; j++)
            {
                if (listsplit[2] == hour[j])
                {
                    string[] datesplit = txt_DATE.Split('-');//splits input date
                    var filename = datesplit[0] + '_' + datesplit[1] + '_' + datesplit[2] + '_' + hour[j] + ".dat";
                    streamWriter = new StreamWriter(new FileStream("C:''" + filename, FileMode.Append, FileAccess.Write));
                }
            }
        }
    }
}

问题是StreamWriter是这样声明的：

private StreamWriter filename;

但随后分配了一个字符串：

filename = datesplit[0] + '_' + dateplit[1] + '_' + datesplit[2] + '_' + hour[j] + '.dat'

建议：文件名和StreamWriter使用单独的变量。

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