多态性、继承和泛型C#:无法将子类强制转换为超类型
本文关键字:子类 转换 类型 超类 继承 泛型 多态性 | 更新日期: 2023-09-27 18:00:12
我在c#中遇到了抽象类和泛型的问题(我通常用Java编码):这是我想使用的代码:
public interface InterfaceResult {...}
public abstract class Result : InterfaceResult {...}
public class ResultA : Result {...}
public class ResultB : Result {...}
public interface InterfaceKing { InterfaceResult function();}
public abstract class King : InterfaceKing {
public abstract Result function();
}
public class KingA : King {
public override ResultA function(){...}
}
public class KingB : King {
public override ResultB function(){...}
}
但这不起作用:Visual Studio希望KingA和KingB使用function()返回Result的实例。如果我使用"new"而不是override,VS说我没有实现所需的方法(我需要使用override)。
所以我尝试了通用,但它并没有更好的
public abstract class Result { }
public class ResultA : Result { }
public class ResultB : Result { }
public interface IKing<T> {T function(); }
public abstract class King<Result> : IKing<Result>
{
public abstract Result function();
public static implicit operator King<Result>(KingB v)
{
return v; // generate StackOverflow Exception
}
public static implicit operator King<Result>(KingA v)
{
throw new NotImplementedException();
}
}
public class KingA : King<ResultA>
{
public override ResultA Get()
{
return new ResultA();
}
}
public class KingB : King<ResultB>
{
public override ResultB Get()
{
return new ResultB();
}
}
public class Test
{
King<Result> a = new KingA(); // allowed by public static implicit operator King<Result>(KingA v)
King<Result> b = new KingB(); // allowed by public static implicit operator King<Result>(KingB v)
KingA ka = new KingA();
List<King<Result>> lista = new List<King<Result>>();
public void test()
{
lista.Add(ka);
}
}
我该怎么做?我找不到任何解决方案,也找不到什么好的或完整的例子。
从"完整接口"到"无接口"(因为没有更好的术语)所有这些都有效(this Main运行良好)
static void Main ()
{
King a = new KingA ();
King b = new KingB ();
KingA ka = new KingA ();
List<King> list = new List<King> ();
list.Add (a);
list.Add (b);
list.Add (ka);
}
"完整界面"
public interface InterfaceResult { }
public abstract class Result : InterfaceResult { }
public class ResultA : Result { }
public class ResultB : Result { }
public interface InterfaceKing { InterfaceResult Function (); }
public abstract class King : InterfaceKing
{
public abstract InterfaceResult Function ();
}
public class KingA : King
{
public override InterfaceResult Function () => new ResultA ();
}
public class KingB : King
{
public override InterfaceResult Function () => new ResultA ();
}
"混合(较少接口)"
public abstract class Result { }
public class ResultA : Result { }
public class ResultB : Result { }
public interface IKing { Result Function (); }
public abstract class King : IKing
{
public abstract Result Function ();
}
public class KingA : King
{
public override Result Function () => new ResultA ();
}
public class KingB : King
{
public override Result Function () => new ResultB ();
{
return new ResultB ();
}
}
"无接口"
public abstract class Result { }
public class ResultA : Result { }
public class ResultB : Result { }
public abstract class King
{
public abstract Result Function ();
}
public class KingA : King
{
public override Result Function () => new ResultA ();
}
public class KingB : King
{
public override Result Function () => new ResultB ();
}
使用协方差
看到了。这里是网络小提琴手。阅读更多关于协方差和反方差的信息
public abstract class Result { }
public class ResultA : Result { }
public class ResultB : Result { }
public interface IKing<out T> where T : Result {}
public abstract class King<T> : IKing<T> where T : Result
{
public abstract T Get();
}
public class KingA : King<ResultA>
{
public override ResultA Get()
{
return new ResultA();
}
}
public class KingB : King<ResultB>
{
public override ResultB Get()
{
return new ResultB();
}
}
public class TestClass
{
King<ResultA> a = new KingA(); // allowed by public static implicit operator King<Result>(KingA v)
King<ResultB> b = new KingB(); // allowed by public static implicit operator King<Result>(KingB v)
KingA ka = new KingA();
List<IKing<Result>> lista = new List<IKing<Result>>();
public void Test()
{
lista.Add(ka);
}
}