带子组的正则表达式简化

本文关键字：正则表达式 | 更新日期: 2023-09-27 18:03:04

是否可以简化以避免重复?最好不要有重复的组。

下面是我的正则表达式的结构化输出:

^(?<Version>('d+)'.('d+)'.('d+))(?!.*['.-]$)(?:(?<IsReleaseVersion>-)(?:(?:(?<RArea1>['da-z]['.'da-z-]+)'.(?<RStep1>['d]+)'.(?<RHash1>['.'da-z]+)'.(?<RCiId1>'d{1,4}))|(?:(?<RArea2>['da-z]['.'da-z-]+)'.(?<RStep2>['d]+)'.(?<RId2>['.'da-z]+))|(?:(?<RArea3>['da-z]['.'da-z-]+)'.(?<RStep3>['d]+))|(?:(?<RArea4>['da-z]['.'da-z-]+))))?(?:(?<IsBuildVersion>'+)(?:(?:(?<BArea1>['da-z]['.'da-z-]+)'.(?<BStep1>['d]+)'.(?<BId2>['.'da-z]+)'.(?<BCiId2>'d{1,4}))|(?:(?<BArea2>['da-z]['.'da-z-]+)'.(?<BStep2>['d]+)'.(?<BId2>['.'da-z]+))|(?:(?<BArea3>['da-z]['.'da-z-]+)'.(?<BStep3>['d]+))|(?:(?<BArea4>['da-z]['.'da-z-]+))))?$

输入文本:

<Version>: (A)=1.0.1 (B)=1.0.1 (C)=1.0.1 (D)=1.0.1 (E)=1.0.1 (F)=1.0.1 (1): (A)=1 (B)=1 (C)=1 (D)=1 (E)=1 (F)=1 (2): (A)=0 (B)=0 (C)=0 (D)=0 (E)=0 (F)=0 (3): (A)=1 (B)=1 (C)=1 (D)=1 (E)=1 (F)=1 <IsReleaseVersion>: (A)=null (B)=null (C)=null (D)=null (E)=null (F)=- <IsBuildVersion>: (A)=+ (B)=+ (C)=+ (D)=+ (E)=null (F)=null <Area>: (A)=beta (B)=beta (C)=beta (D)=beta (E)=null (F)=beta <Step>: (A)=1 (B)=1 (C)=1 (D)=null (E)=null (F)=1 <Id>: (A)=abcd1234 (B)=abcd1234 (C)=null (D)=null (E)=null (F)=abcd1234 <CiId>: (A)=0001 (B)=null (C)=null (D)=null (E)=null (F)=null

我希望任何人都能帮助我!

带子组的正则表达式简化

天哪，你弄得一团糟:)我只关注这一部分:

((?:(?:(?<RArea1>['da-z]['.'da-z-]+)'.(?<RStep1>['d]+)'.(?<RHash1>['.'da-z]+)'.(?<RCiId1>'d{1,4}))|
(?:(?<RArea2>['da-z]['.'da-z-]+)'.(?<RStep2>['d]+)'.(?<RId2>['.'da-z]+))|
(?:(?<RArea3>['da-z]['.'da-z-]+)'.(?<RStep3>['d]+))|
(?:(?<RArea4>['da-z]['.'da-z-]+)))

可以重写为:

(?:(?<Area>['da-z]+)(?:'.(?<Step>['d]+)(?:'.(?<Hash>['da-z]+)(?:'.(?<CiId>'d{1,4}))?)?)?)

简单地嵌套条件。

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