上传文件到webservice并下载它返回的文件

本文关键字：文件 返回 下载 webservice | 更新日期: 2023-09-27 18:03:30

嗨，我正在使用GZipStream压缩xml文件并将其上传到一个webservice，该webservice将返回我必须下载的GZipStream。我在c#中使用WebClient使用以下方法，但它抛出异常"WebClient不支持并发I/O操作"。

byte[] data = Encoding.ASCII.GetBytes(xml);
                    MemoryStream input = new MemoryStream(data);
                    MemoryStream output = new MemoryStream();
                    GZipStream zip = new GZipStream(output, CompressionMode.Compress);
                    input.WriteTo(zip);
                    byte[] gzipStream = output.ToArray();
                    //Constructing Request
                    var postClient = new WebClient();
                    Uri uri = new Uri(url);
                    postClient.UploadDataAsync(uri, gzipStream);
                    var resStream = new GZipStream(postClient.OpenRead(url),CompressionMode.Decompress);
                var reader = new StreamReader(resStream);
                var textResponse = reader.ReadToEnd();
                return textResponse;

请帮帮我。

上传文件到webservice并下载它返回的文件

在这种情况下不应该使用async

byte[] data = Encoding.ASCII.GetBytes(xml);
                MemoryStream input = new MemoryStream(data);
                MemoryStream output = new MemoryStream();
                GZipStream zip = new GZipStream(output, CompressionMode.Compress);
                input.WriteTo(zip);
                byte[] gzipStream = output.ToArray();
                //Constructing Request
                var postClient = new WebClient();
                Uri uri = new Uri(url);
                postClient.UploadData(uri, gzipStream);
                var resStream = new GZipStream(postClient.OpenRead(url),CompressionMode.Decompress);
            var reader = new StreamReader(resStream);
            var textResponse = reader.ReadToEnd();
            return textResponse;
或者你应该等待async操作(如果你的方法是async): 
byte[] data = Encoding.ASCII.GetBytes(xml);
                MemoryStream input = new MemoryStream(data);
                MemoryStream output = new MemoryStream();
                GZipStream zip = new GZipStream(output, CompressionMode.Compress);
                input.WriteTo(zip);
                byte[] gzipStream = output.ToArray();
                //Constructing Request
                var postClient = new WebClient();
                Uri uri = new Uri(url);
                await postClient.UploadDataAsync(uri, gzipStream);
                var resStream = new GZipStream(postClient.OpenRead(url),CompressionMode.Decompress);
            var reader = new StreamReader(resStream);
            var textResponse = reader.ReadToEnd();
            return textResponse;
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