通过每个元素C#的子字符串对字符串数组进行排序

本文关键字：字符串 数组 排序 元素 | 更新日期: 2023-09-27 18:03:36

所以，假设我有一个字符串数组

    string[] stringArray = new string[5] { "3 Three", "8 Eight", "6 Six", "13 Thirteen", "24 Twenty Four";

我想选择每个字符串元素中的第一个数字，并按升序对该数组进行排序'我希望结果是使用时：

    Console.Writeline(String.Format("{0}, {1} and {2} are the lowest elements", stringArray[0], stringArray[1], stringArray[2]))

显示："3三、6六和8八是最低元素">

通过每个元素C#的子字符串对字符串数组进行排序

您可以将String.Split和int.Parse与LINQ:一起使用

stringArray = stringArray.OrderBy(s => int.Parse(s.Split()[0])).ToArray();

另一种更有效但可读性较差的方法是Array.Sort:

Array.Sort(stringArray, (s1, s2) => int.Parse(s1.Split()[0]).CompareTo(int.Parse(s2.Split()[0])));

像这样的东西应该可以完成

  string[] stringArray = new string[5] { "3 Three", "8 Eight", "6 Six", "13 Thirteen", "24 Twenty Four" };
  var ordered = stringArray.Select(s => new { number = int.Parse(s.Split(' ')[0]), text = s.Split(' ')[1] }).OrderBy(i => i.number).Select(arg => arg.number + " " + arg.text).ToArray();
  Console.WriteLine($"{ordered[0]}, {ordered[1]} and {ordered[2]} are the lowest elements");

或者在你的简单场景中：

var ordered = stringArray.OrderBy(s => int.Parse(s.Split(' ')[0])).ToArray();
Console.WriteLine($"{ordered[0]}, {ordered[1]} and {ordered[2]} are the lowest elements");

string[] stringArray = new string[5] { "3 Three", "8 Eight", "6 Six", "13 Thirteen", "24 Twenty Four"};
string[] orderedArray = stringArray.OrderBy(ele => Convert.ToInt32(ele.Split(' ')[0])).ToArray();
Console.Writeline(String.Format("{0}, {1} and {2} are the lowest elements", orderedArray[0], orderedArray[1], orderedArray[2]))

使用上述代码。

与其拆分或解析字符串，不如先按第一个空间的索引排序，然后按字符串排序：

string[] stringArray = { "3 Three", "8 Eight", "6 Six", "13 Thirteen", "24 Twenty Four" };
var ordered = stringArray.OrderBy(s => s.IndexOf(' ')).ThenBy(s => s).ToArray();
Debug.Print(string.Join(", ", ordered)); // "3 Three, 6 Six, 8 Eight, 13 Thirteen, 24 Twenty Four"
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