TinyIoC解析插件合同

如何使用TinyIoC解析插件联系人?

Host.exe/w引用Core.Contract.dll

var container = new TinyIoCContainer();
container.AutoRegister(new[] { Assembly.LoadFrom("Core.Contracts.dll") }, 
                DuplicateImplementationActions.RegisterMultiple);
container.AutoRegister(new[] { Assembly.LoadFrom("EchoCodeAnalysis.dll") }, 
                DuplicateImplementationActions.RegisterMultiple);
var mi = container.Resolve<IService>();

在Core.Contracts.dll中的contract IService和它在宿主程序集中的引用，这是为了让拖放插件有机会在不重新编译的情况下工作。在EchoCodeAnalysis.dll中，我们有实际的插件实现，它没有在宿主程序集中引用，而是使用IService共享Core.Contracts.dll的宿主。

Core.Contract.dll:

public interface IService
{
    string ID { get; set; }
}

EchoCodeAnalysis.dll:

public class Service : IService
{
    string IService.ID
    {
        get
        {
            throw new NotImplementedException();
        }
        set
        {
            throw new NotImplementedException();
        }
    }
}

编辑:

我设法解决了问题的第一部分。

var type = typeof(IService);
var types = (new[] { Assembly.LoadFrom("EchoCodeAnalysis.dll") }).ToList()
                .SelectMany(s => s.GetTypes())
                .Where(x => type.IsAssignableFrom(x) && x.IsClass).ToList();
container.RegisterMultiple<IService>(types.ToArray());
var mi = container.ResolveAll<Core.Contracts.IService>();

将获取并解析所有IService接口，这将插件限制为该接口，而不是任何高层实现。比如说，IMenuItem被实现为IService，上面的代码可以找到任何可以追溯到IService起源的类，但是那些显式实现了IMenuItem的类，当它被解析为IService时，它只会获取IService属性，而不包括IMenuItem属性。这就是。container.Register(types.ToArray()). asrespectiveimplementations()会派上用场。但是这个问题还有别的解决办法吗?还是必须编写一个实用程序来扩展TinyIOC?

编辑2:

我们已经转移到扩展，但我们仍然没有得到任何解决。

    public static IEnumerable<T> GetPluginsForModule<T>()
    {
        var type = typeof(T);
        var types = Plugins.SelectMany(s => s.GetTypes())
            .Where(x => type.IsAssignableFrom(x) && x.IsClass).ToList();
        foreach (var t in types)
        {
            if (t.CustomAttributes.Where(x => x.AttributeType == typeof(CluraPlugin)).Any()) 
            {
                CustomAttributeData attr = t.CustomAttributes.Where(x => x.AttributeType == typeof(CluraPlugin)).FirstOrDefault();
                if (attr == null)
                    break;
                string Name = attr.ConstructorArguments.Where(x => x.ArgumentType == typeof(string)).FirstOrDefault().Value as string;
                Type InterfaceTypeArgument = attr.ConstructorArguments.Where(x => x.ArgumentType == typeof(Type)).FirstOrDefault().Value as Type;
                Container.Register(InterfaceTypeArgument, t, Name).AsMultiInstance();
            }
        }
        return Container.ResolveAll(type) as IEnumerable<T>;
    }

我传递正确的值，在容器中。上面的寄存器有InterfaceTypeArgument = IMenuItem, t = EchoMenu: IMenuItem, Name = "EchoMenu"但是当我们要求容器在注册EchoMenu作为其实现后解析IMenuItem时，我们从resolall返回null。

任何想法吗?

string PluginDirectory = Directory.GetCurrentDirectory() +"''Plugins''";
PluginManager.LoadDirectory(PluginDirectory);
var mi = PluginManager.GetPluginsForModule<IService>();

public static IEnumerable<object> GetPluginsForModule<T>()
{
    var type = typeof(T);
    var types = Plugins.SelectMany(s => s.GetTypes())
            .Where(x => type.IsAssignableFrom(x) && x.IsClass).ToList();
    foreach (var t in types)
    {
        if (t.CustomAttributes.Where(x => x.AttributeType == typeof(CluraPlugin)).Any()) 
        {
           CustomAttributeData attr = t.CustomAttributes.Where(x => x.AttributeType == typeof(CluraPlugin)).FirstOrDefault();
           if (attr == null)
              break;
           string Name = attr.ConstructorArguments.Where(x => x.ArgumentType == typeof(string)).FirstOrDefault().Value as string;
           Type InterfaceTypeArgument = attr.ConstructorArguments.Where(x => x.ArgumentType == typeof(Type)).FirstOrDefault().Value as Type;
           Container.Register(InterfaceTypeArgument, t, Name).AsMultiInstance();
         }
     }
     return Container.ResolveAll(type);
}