Linq to xml Select statement
本文关键字:statement Select xml to Linq | 更新日期: 2023-09-27 18:06:22
我想弄清楚如何使用linq到xml做一个选择语句。如果DeploymentType等于一个特定的值(Enterprise9999),我想返回ServerTypes。
XML:<Deployments>
<Deployment>
<DeploymentType>Enterprise9999</EnterpriseDeploymentType>
<Servers>
<DeploymentServer>
<ServerType>WindowsServer</ServerType>
</DeploymentServer>
<DeploymentServer>
<ServerType>LinuxServer</ServerType>
</DeploymentServer>
</Servers>
</Deployment>
<Deployment></Deployment>
<Deployment></Deployment>
</Deployments>
这是到目前为止我在代码中的内容。我确定我用错了方法:
XDocument xmlDoc = XDocument.Load(@xmlFile);
IEnumerable<XElement> xlDeployments = from depRows in xmlDoc.Descendants("Deployments")
select depRows;
var deploy = xlDeployments.Descendants("Deployment");
foreach (var dep in deploy)
{
if (dep.Element("DeploymentType").ToString() == "Enterprise9999")
{
MessageBox.Show(dep.Elements("ServerType").ToString());
}
}
选择语句需要命名空间吗?
我把你的标签</EnterpriseDeploymentType>
改成了</DeploymentType>
XDocument xmlDoc = XDocument.Load(@xmlFile);
var deployments = xmlDoc.Descendants("Deployment")
.Where(dep => dep.Element("DeploymentType") != null
&& dep.Element("DeploymentType").Value == "Enterprise9999");
var servers = deployments.Descendants("ServerType")
.Select(node => node.Value);
Console.WriteLine(string.Join(Environment.NewLine, servers));
打印:
WindowsServer
LinuxServer
假设您已经按照我的评论更正了您的XML,您可以使用以下单个查询:-
var nodes = from n in xml.Descendants("DeploymentType")
.Where(x => x.Element("EnterpriseDeploymentType").Value.Equals("Enterprise9999"))
select n.Descendants("Servers").Descendants("ServerType").Select(s => s.Value);
这将给你:
WindowsServer
LinuxServer